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2 years ago

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Which equation describes a line that passes through (-5,-8) and is perpendicular to y= 5/4x + 10

1 answer:

lara31 [8.8K]2 years ago

8 0

Answer: y = -4/5x - 12

1. First find slope. Since you are trying to find a line perpendicular to y = 5/4x + 10, the slope would be the negative reciprocal of 5/4x.

slope = - 4/5x

2. plug in (-5,-8) and the slope of -4/5 to the point slope form equation
(y-y2) = slope (x-x2)

= y+8=-4/5(x+5)

3. solve and simply y+8=-4/5(x+5)

y = -4/5x - 12 is your answer

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Consider the equation 2(ax+3)=4x−3(4x+8). For what value of a is there no solution to the equation?

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Answer:

the value of $a$ such that there is no solution to the equation is $a = -4$ .

Step-by-step explanation:

Let first simplify the expression presented on statement. The equation has no solution if and only if $a$ is eliminated in the process and an absurd is the result (i.e. $0 = 7$ ).

$2\cdot (a\cdot x + 3) = 4\cdot x -3\cdot (4\cdot x + 8)$

$2\cdot a\cdot x +6 = 4\cdot x -12\cdot x -24$

$2\cdot a \cdot x+6=-8\cdot x-24$

$2\cdot a\cdot x +8\cdot x = -30$

$2\cdot (a+4)\cdot x = -30$

$(a+4)\cdot x = -15$

To obtain an absurd, we need that $a+4 = 0$ . Hence, the value of $a$ such that there is no solution to the equation is:

$a = -4$

Let prove the certainty of the result. We find that an absurd exist: ( $a = -4$ )

$0 = -15$

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