Answer:
The lower bound of a 99% C.I for the proportion of defectives = 0.422
Step-by-step explanation:
From the given information:
The point estimate = sample proportion 
= 0.55
At Confidence interval of 99%, the level of significance = 1 - 0.99
= 0.01
Then the margin of error 
E = 0.128156
E ≅ 0.128
At 99% C.I for the population proportion p is: 
= 0.55 - 0.128
= 0.422
Thus, the lower bound of a 99% C.I for the proportion of defectives = 0.422
Answer:
P = 1039.5
Step-by-step explanation:
Given:-
- The initial amount deposited, Po = 500
- The interest rate applied, I = 5% compounded annually
Find:-
- The amount on her bank statement after 15 years?
Solution:-
- We see that the principal amount increases every year and no transactions have been made in the course of 15 years.
The total amount left in her savings account would be given by the following formula:
P = Po * ( 1 + I/100 )^n
- Where, n = number of years passed since deposit. (15 years)
P = 500 * ( 1 + 5/100 )^15
P = 500 * (1.05)^15
P = 1039.5
Answer: I think 2 4/39
Step-by-step explanation: not sure sorry if i get it wrong
Simply take a ruler with centimeters on it and measure your desk.Tell the teacher you counted how many centimeters.
