Question

A bag contains 4 Red, 5 Black and 2

Answer 1

Answer:

$P( 2 \ green ) = \frac{4}{121}$

Step-by-step explanation:

$Probability \ of \ green \ i n \ the \ first \ try = \frac{2C_1}{11C_1} = \frac{2}{11}\\\\Probability \ of \green \ i n \ the \ Second \ try = \frac{2C_1}{11C_1} = \frac{2}{11}\\\\Probability \ of \ 2 \ green = \frac{2}{11} \times \frac{2}{11 } = \frac{4}{121}$