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Finger [1]
3 years ago
7

How can I solve this quadratic using the square root properly?

Mathematics
2 answers:
Citrus2011 [14]3 years ago
7 0

Answer:

x = <u>+</u>3

Step-by-step explanation:

4x² = 36

sqareroot both side we get,

√4x² = √36

2x = 6

x = 6/2

x = <u>+</u>3

Thus, The answer is <u>+</u>3

<u>-TheUnknown</u><u>S</u><u>cientist</u>

Iteru [2.4K]3 years ago
6 0

Answer:

4x^2 = 36

________ x^2 = 9. square root of 9

4. = 4. x = 3

Step-by-step explanation:

Divide both sides by 4 to isolate the square root.

So, you will end up with x^2 = 9

then take the square root of 9,

square root of 9 is 3.

So x = 3

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Write an expression that means "the sum of six and the product of three and d"
kolezko [41]

Answer:

6+3d

Step-by-step explanation:

Sum would be adding 6 and a number, and product is 3 and d. So, it would be 6+3d.

3 0
3 years ago
Find the cosine of ∠D.
Alina [70]

Answer:

5/13

Step-by-step explanation:

Using SOHCAHTOA

Cosine of D = adjacent / hypotenuse

Cosine of D = 5 / 13

8 0
2 years ago
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3 years ago
At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 36 m
Degger [83]

The probability that a randomly selected customer will have to wait between 32 minutes and 37 minutes is 59.81%

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Z score is given by:

z = (raw score - mean) / standard deviation

Given mean of 36 minutes and a standard deviation of 3 minutes.

For x = 32:

z = (32 - 36)/3 = -1.33

For x = 37:

z = (37 - 36)/3 = 0.33

P(-1.33 < z < 0.33) = P(z < 0.33) - P(z < -1.33) = 0.6179 - 0.0198 = 0.5981

The probability that a randomly selected customer will have to wait between 32 minutes and 37 minutes is 59.81%

Find out more on equation at: brainly.com/question/2972832

#SPJ1

7 0
2 years ago
Bella bought and candies ?
kondor19780726 [428]

Hmm I’ve done this before but I can’t remember sorry but I will try and think
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3 years ago
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