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scZoUnD [109]
3 years ago
10

F(x) = x2 + 2x + 1, find f(x + h) and simplify.

Mathematics
1 answer:
mario62 [17]3 years ago
3 0

Given:

The function is

f(x)=x^2+2x+1

To find:

The value of f(x+h) in simplified form.

Solution:

We have,

f(x)=x^2+2x+1

Putting x=x+h, we get

f(x+h)=(x+h)^2+2(x+h)+1

f(x+h)=x^2+2xh+h^2+2x+2h+1

f(x+h)=x^2+h^2+2xh+2x+2h+1

Therefore, the simplified value of f(x+h) is x^2+h^2+2xh+2x+2h+1.

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A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra
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Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

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Step-by-step explanation:

Given

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Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

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r = \sqrt{(a)^2 + (b)^2}

Since a belongs to the x axis and b belongs to the y axis;

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cos\theta = \frac{a}{r}

Substitute r = \sqrt{(a)^2 + (b)^2}

cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}

cos\theta = \frac{a}{\sqrt{a^2 + b^2}}

Rationalize the denominator

cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}

cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

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