The change in velocity of the baseball is 39.72 m/s
<h3>What is change in velocity?</h3>
This is the difference between the final and the initial velocity of a body.
To calculate the change in velocity of the ball, we use the formula below.
<h3>Formula:</h3>
- Ft = mΔv.............. Equation 1
Where:
- F = Force exerted by the person
- t = time
- m = mass of the baseball
- Δv = Change in velocity.
Make Δv the subject of the equation
- Δv = Ft/m........... Equation 2
From the question,
Given:
- F = 12 N
- t = 0.480 s
- m = 0.145 kg
Substitute these values into equation 2
- Δv = (12×0.48)/0.145
- Δv = 39.72 m/s.
Hence, The change in velocity of the baseball is 39.72 m/s
Learn more about change in velocity here: brainly.com/question/112886
Cost of vehicle, cost per launch, capacity of each vehicle, re-usability, size of vehicle, etc
Answer:
Explanation:
L 1: front radius 950 mm, rear radius 2700 mm, refractive index 1.528;
We shall use lens maker's formula , that is
1/f = (μ-1) ( 1/R₁ - 1/R₂) , μ is refractive index of the lens , R₁ and R₂ are radius of curvature of front and rear curved surface.
1/f₁ = (1.528-1)( 1/950 + 1/2700)
f₁ = 1331 mm
L2: front radius 535 mm, rear radius 500 mm, refractive index 1.550.
1/f₂ = (1.550-1)( 1/535 + 1/500)
f₂ = 470 mm
largest angular magnification possible
= f₁ /f₂
= 1331 / 470
= 2.83 ( approx )
Length between two lenses
=1331 +470
= 1801 mm
= 1.8 m Ans
Answer:
at R/
Explanation:
The free-fall acceleration at the surface of Earth is given by
where
G is the gravitational constant
M is the Earth's mass
R is the Earth's radius
The formula can be rewritten as
(1)
We want to shrink the Earth at a radius R' such that the acceleration of gravity becomes 3 times the present value, so
g' = 3g
Keeping the mass constant, M, and substituting into the equation, we have
Answer:
x(t) = 0.077cos(6.455t)
Explanation:
If the spring can be stretched 0.2 m by a force of 50 N, then the spring constant is:
k = 50 / 0.2 = 250 N/m
The equation of simple harmonic motion is as the following:
where 
We also know that the initial velocity is 0.5 m/s, which is also the maximum speed at the equilibrium:
is the initial phase
Therefore, the position of the mass after t seconds is
x(t) = 0.077cos(6.455t)
