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RideAnS [48]
4 years ago
14

In circular orbit, the gravitational force on a satellite is A. constant in magnitude. B. at right angles to satellite motion. C

. Both of these. D. Neither of these
Physics
2 answers:
VARVARA [1.3K]4 years ago
7 0

The answer should be C.

steposvetlana [31]4 years ago
6 0

I would say C. if im wrong, im sorry. but if im right your welcome. i didnt guess tho.

You might be interested in
A 1.0 C charged object and a 2.0 C charged object are separated by 100 m. Where should a -1.0x10-3 C charged object be placed on
horsena [70]

Answer:

x = 41.2 m

Explanation:

The electric force is a vector magnitude, so it must be added as vectors, remember that the force for charges of the same sign is repulsive and for charges of different sign it is negative.

In this case the fixed charges (q₁ and q₂) are positive and separated by a distance (d = 100m), the charge (q₃ = -1.0 10⁻³ C)) is negative so the forces are attractive, such as loads q₃ must be placed between the other two forces subtract

             F = F₁₃ - F₂₃

let's write the expression for each force, let's set a reference frame on the charge q1

           F₁₃ = k \frac{q_1 q_3}{x^2}

           F₂₃ = k \frac{q_2 q_3}{(d-x)^2}

they ask us that the net force be zero

           F = 0

           0 = F₁₃ - F₂₃

           F₁₃ = F₂₃

          k \frac{q_1 q_3}{x^2} =k \frac{q_2 q_3}{(d-x)^2}

          \frac{q_1}{x^2} = \frac{q_2}{(d-x)^2 }q1 / x2 = q2 / (d-x) 2

       

           (d-x)² = \frac{q_2}{q_1} x²

we substitute

           (100 - x)² = 2/1  x²

           100- x = √2  x

           100 = 2.41 x

           x = 41.2 m

6 0
3 years ago
What type of lever has the fulcrum between the resistance arm and the effort arm?
crimeas [40]
I’m not really sure but I think it’s D type 1 lever
4 0
3 years ago
The driver or a sports car traveling at 10 m/s steps down hard on the accelerator for 5 seconds. If they accelerate at a rate of
ivanzaharov [21]

Answer:

53.125m

Explanation:

The displacement of the car, denoted by S, can be calculated using the formula:

S = ut + 1/2at²

Where;

u = initial velocity/speed (m/s)

t = time (s)

a = acceleration (m/s²)

According to the information provided in this question, u = 10m/s, t = 5s, a = 0.25m/s², S = ?

S = ut + 1/2at²

S = (10 × 5) + 1/2 (0.25 × 5²)

S = 50 + 1/2 (0.25 × 25)

S = 50 + 1/2(6.25)

S = 50 + 3.125

S = 53.125m

4 0
3 years ago
You and a friend are playing with a bowling ball to demonstrate some ideas of Rotational Physics. First, though, you want to cal
RideAnS [48]

Answer:

K_{total} = 19.4 J

Explanation:

The total kinetic energy that is formed by the linear part and the rotational part is requested

         K_{total} = K_{traslation}  + K_{rotation}

let's look for each energy

linear

        K_{traslation} = ½ m v²

rotation

        K_{rotation} = ½ I w²

the moment of inertia of a solid sphere is

       I = 2/5 m r²

we substitute

       K_{total} = ½ mv² + ½ I w²

           

angular and linear velocity are related

           v = w r

we substitute

           K_{total} = ½ m w² r² + ½ (2/5 m r²) w²

           K_{total} = m w² r² (½ + 1/5)

           K_{total} = \frac{7}{10} m w² r²

let's calculate

           K_{total} = \frac{7}{10}   6.40 16.0² 0.130²

           K_{total} = 19.4 J

6 0
3 years ago
3. A bicycle has a momentum of 25.00 kg* m/s and a velocity of 2.5 m/s . What is the bicycle's
Anna35 [415]

Answer:

10 kg

Explanation:

The question is most likely asking for the mass of the bicycle.

Momentum is the product of an object's mass and velocity. Mathematically:

p = m * v

Where p = momentum

m = mass

v = velocity

Hence, mass is:

m = p / v

From the question:

p = 25 kgm/s

v = 2.5 m/s

Mass is:

m = 25 / 2.5 = 10 kg

The mass of the bicycle is 10 kg.

In case the question requires the Kinetic energy of the bicycle, it can be gotten by using the formula

K. E = ½ * p * v

K. E. = ½ * 25 * 2.5 = 31.25 J

5 0
4 years ago
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