Answer:
V = 1.578m/s
Explanation:
(Ma x Ua) + (Mb x Ub) = (Ma + Mb)V
(13500 x 4.5) + (25000 x 0) = (13500 + 25000)V
60750 + 0 = (38500)V
60750 = 38500V
V = 60750/38500
V = 1.578m/s
Answer:
8 seconds, Answer choice C.
Explanation:
The information they give us about the speed of the cat, is from the point at which the dog started chasing it (that velocity being 10 m/s).
Notice that the actual distance the cat run is: 100 meters minus 20 meters (100 - 20 = 80 meters). Therefore, we have information on the distance covered by the cat (80 meters), and its speed (10 m/s), so we can use the definition of speed to find the time it took the cat to get to the tree:
Since all units for the physical quantities involved were given in the SI system, the answer comes also in the SI units of time: "seconds"
Answer:
<em>Ceteris Paribus</em>
Explanation:
The process of examining a change in one variable in a model while assuming that all the other variables remain constant is called <em><u>Ceteris Paribus</u></em>.
<em>Ceteris Paribus</em> is a Latin phrase that means "all other things being equal" or "all other things held constant" in English. The phrase has found application in disciplines like Economics and Statistics. This phrase as being adopted as a process of examining a change in one variable in a model while assuming that all the other variables remain constant to ascertain the relationship between the variables or make deductions from an experimental study. An example of <em>Ceteris Paribus</em> application is the law of demand and supply in Economics. The law of demand states, <em>Ceteris Paribus</em>, the higher the price, the lower the quantity demanded and <em>vice versa. </em>Conversely, the law of supply states, <em>Ceteris Paribus</em>, the higher price, the higher the quantity supply and <em>vice versa</em>.
Given Information:
Radius = ra = 2.60 cm = 0.026 m
Density = J = 15.0 nC/m
change in potential difference = ΔV = 200 V
Required Information:
Distance = d = ?
Answer:
distance = 0.088 m
Explanation:
As we know
ΔV = Vb - Va = J/4πε₀*ln(rb/ra)
Where ra and rb is the point where potential difference is Va and Vb respectively
1/4πε₀ = 9x10⁹ N.m²/C²
We want to find the distance d = rb - ra
ΔV = J/4πε₀*ln(rb/ra)
200 = 9x10⁹*15x10⁻⁹*ln(rb/ra)
200/135 = ln(rb/ra)
1.48 = ln(rb/ra)
taking e on both sides yields
e^(1.48) = rb/ra
4.39 = rb/ra
rb = 4.39*0.026
rb = 0.114 m
Therefore, the required distance is
d = rb - ra
d = 0.114 - 0.026
d = 0.088 m
Therefore, the other probe must be placed 0.088 m from the surface so that the voltmeter reads 200 V
