Answer:
Balanced Chemical equation:
4Na + O₂ → 2Na₂O
Explanation:
Chemical equation:
Na + O₂ → Na₂O
Balanced Chemical equation:
4Na + O₂ → 2Na₂O
Four mole of sodium combine with one mole of oxygen and form two mole of sodium oxide.
Coefficient with reactant and products:
Na 4
O₂ 1
Na₂O 2
Oxygen is present in group sixteen and have six valance electrons. while sodium is alkali metal and present in group one and have one valance electron.
Oxygen needs two electron to complete the octet while sodium need to lose the one electron to get the complete octet.
When oxygen is combine with sodium it gain its two valance electrons from two sodium atom and form anion while sodium loses its valance electron to wards oxygen and form cation. The bond form between them is ionic because one is metal and other is non metal and electrons are completely transfer from two sodium atom to one oxygen atom.
Answer:
Explanation:
As given in the question that methane(
) is taken excess amount
mass of 
depend only on mass of fluorine
mass of 
=180 g
mole of =
=9.47
3 mole of gives 1 mole of
so 1 mole will give 
mole of
therefore,
9.47 mole of will give 
mole of
Answer:
The answer would be 0.198 liters.
Explanation:
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Answer:
H₂O, Na⁺, and SO₄²⁻
Explanation:
NaOH and H₂SO₄ are strong electrolytes. They will ionize completely
.
Molecular equation: 2NaOH + H₂SO₄ ⟶ Na₂SO₄ + 2H₂O
Ionic equation: 2Na⁺ + 2OH⁻ + 2H⁺ + SO₄²⁻ ⟶ 2Na⁺ + SO₄²⁻+ 2H₂O
- The concentration of water is 55.5 mol·L⁻¹.
- The concentration of Na⁺ is twice that of SO₄²⁻ .
- Hydrolysis of SO₄²⁻ is negligible.
The principal components in the flask at the endpoint are H₂O, Na⁺, and SO₄²⁻.
Density=mass/volume so once you find the mass and volume of a substance you can then calculate the density
