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elena-14-01-66 [18.8K]

3 years ago

13

If 25.0 mL of 0.451 M NaOH solution is titrated with 0.253 M H2SO4, the flask at the endpoint will contain (besides the indicato

r phenolphthalein) as the principal components:

1 answer:

tigry1 [53]3 years ago

4 0

Answer:

H₂O, Na⁺, and SO₄²⁻

Explanation:

NaOH and H₂SO₄ are strong electrolytes. They will ionize completely .

Molecular equation: 2NaOH + H₂SO₄ ⟶ Na₂SO₄ + 2H₂O

Ionic equation: 2Na⁺ + 2OH⁻ + 2H⁺ + SO₄²⁻ ⟶ 2Na⁺ + SO₄²⁻+ 2H₂O

The concentration of water is 55.5 mol·L⁻¹.
The concentration of Na⁺ is twice that of SO₄²⁻ .
Hydrolysis of SO₄²⁻ is negligible.

The principal components in the flask at the endpoint are H₂O, Na⁺, and SO₄²⁻.

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How many copper atoms are in 70g of copper

Elanso [62]

Answer:

$n = 6.634\times 10^{23}\,atoms$

Explanation:

The total amount of atoms is found by multiplying Avogradro's Number and the number of moles:

$n = \left(6.022\times 10^{23}\,\frac{atoms}{mol} \right)\cdot \left(\frac{70\,g}{63.546\,\frac{g}{mol} } \right)$

$n = 6.634\times 10^{23}\,atoms$

4 0

3 years ago

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Pani-rosa [81]

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas Mole Fraction kH mol/(L*atm)

$N_2$ $7.81\times 10^{-1}$ $6.70\times 10^{-4}$

$O_2$ $2.10\times 10^{-1}$ $1.30\times 10^{-3}$

Ar $9.34\times 10^{-3}$ $1.40\times 10^{-3}$

$CO_2$ $3.33\times 10^{-4}$ $3.50\times 10^{-2}$

$CH_4$ $2.00\times 10^{-6}$ $1.40\times 10^{-3}$

$H_2$ $5.00\times 10^{-7}$ $7.80\times 10^{-4}$

<u>Answer:</u> The solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

<u>Explanation:</u>

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

$p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}$

where,

$p_A$ = partial pressure of hydrogen gas = ?

$p_T$ = total pressure = 0.380 atm

$\chi_A$ = mole fraction of hydrogen gas = $5.00\times 10^{-7}$

Putting values in above equation, we get:

$p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm$

To calculate the molar solubility, we use the equation given by Henry's law, which is:

$C_{H_2}=K_H\times p_{H_2}$

where,

$K_H$ = Henry's constant = $7.80\times 10^{-4}mol/L.atm$

$p_{H_2}$ = partial pressure of hydrogen gas = $1.9\times 10^{-7}atm$

Putting values in above equation, we get:

$C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M$

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is $1.48\times 10^{-10}M$

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3 years ago

What coefficient should be used to make the following equation balanced? N2+O2--> _NO

IgorLugansk [536]

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Your answer should be:

N2 + O2 → 2NO

<h2>····················································································</h2>

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7 0

2 years ago

How many protons does a nitrogen atom have?<br> 07<br> 0 14<br> 8<br> 05

VLD [36.1K]

Answer:

07.

Explanation:

8 0

2 years ago

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An 80 kg long jumper in flight accelerates at a rate of 10 m/s^2. What is the force of the long jumper

Katarina [22]

Answer:

F = 800 N

Explanation:

Given data:

Mass = 80 Kg

Acceleration = 10 m/s²

Force = ?

Solution:

Formula:

<em>F = m × a </em>

F = force

m = mass

a = acceleration

Now we will put the values in formula:

<em>F = m × a </em>

F = 80 kg <em>× </em>10 m/s²

F = 800 kg.m/s²

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3 years ago