Zn = 28.15%
Cl = 30.53%
O = 41.32%
<h3>Further explanation</h3>
Given
Zn(CIO3)2 compound
Required
The % composition
Solution
Ar Zn = 65.38
Ar Cl = 35,453
Ar O = 15,999
MW Zn(CIO3)2 = 232.3
Zn = 65,38/232.3 x 100% = 28.15%
Cl = (2 x 35.453) / 232.3 x 100% = 30.53%
O = (6 x 15.999) / 232.3 x 100% = 41.32%
Answer:
The pellet fraction will be most radioactive because the heavy protein part of ghost will be present in the the pellet fraction.
Explanation:
supernatant can be defined as a liquid part that lies above the sediment of the centrifuge tube on the other hand pallet is a solid material present at the bottom end of the centrifuge tube.
As protein molecules in the given experiment is radio labelled that"s why the pellet fraction will be radio labeling part because the heavy protein molecules will be present in the pellet fraction.
Through manipulation of equations, we are able to obtain the equation:
Then we can transform the equation into:
Then we are able to plug in the pOH and directly get [OH-]: