The grams of Mg(OH)2 produced is calculated as below
calculate the moles of HCl produced =molarity xvolume/1000
= 0.3 x 435/1000= 0.1305 moles
write the equation for reaction
Mg(OH)2 +2HCl = MgCl2 + 2H2O
by use of mole ratio between HCl :MgCl2 which is 2 :1 the moles of HCl = 0.1305 x1/2 =0.0653 moles of MgCl2
mass of MgCl2 = moles x molar mass
= 0.0653mol x95 g/mol = 6.204 grams of MgCl2
The answer to this is yes they are likely, true.
<u>Given:</u>
MilliMoles of N2 = 2.5 mmol = 0.0025 moles
Initial volume V1 = 42 cm3
Final volume V2 = 600 cm3
Temperature T = 300 K
<u>To determine:</u>
The change in Gibbs free energy, ΔG
<u>Explanation:</u>
The change in Gibbs free energy is related to the ration of the volumes:
ΔG = -nRTln(V2)/(V1)
= -0.0025*8.314*300*ln(600/42) = -16.582 J/mol
Ans: The Gibbs free energy for the process is 0.0166 kJ/mol
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ヾ(￣▽￣) Hello :)
It is neutrons so it is right I tell you
