The purpose of this process is to make sure that the substance is completely melted before trying to figure up the mass. if there are still bits of solid in the liquid the mass will be incorrect if just taken the first time. Also, some substances have gaseous elements in them so to heat it up, it releases those gases and you’re left with the true mass in the liquid.
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The answer will be 180.156 g/mol
For the purpose we will use solution dilution equation:
c1xV1=c2xV2
Where, c1 - concentration of stock solution; V1 - a volume of stock solution needed to make the new solution; c2 - final concentration of new solution; V2 - final volume of new solution.
c1 = 3.00 M
c2 = 1.25 M
V1 = ?
V2 = 0.195 L
When we plug values into the equation, we get following:
3 x V1 = 1.25 x 0.195
V1 = 0.08 L
Answer:
VP as function of time => VP(Ar) > VP(Ne) > VP(He).
Explanation:
Effusion rate of the lighter particles will be higher than the heavier particles. That is, the lighter particles will leave the container faster than the heavier particles. Over time, the vapor pressure of the greater number of heavier particles will be higher than the vapor pressure of the lighter particles.
=> VP as function of time => VP(Ar) > VP(Ne) > VP(He).
Review Graham's Law => Effusion Rate ∝ 1/√formula mass.