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Convert the following temperatures to degrees Celsius or Fahrenheit: (a) 95Â°F, the temperature on a hot summer day; (b) 12Â°F,

Elis [28]

Answer:

a) 35°C, the temperature on a hot summer day

b) -11.11°C, the temperature on a cold winter day

c) a 38.88°C fever

d) a furnace operating at 1011.11°C

e) 523.67°F ( theoretically the lowest attainable temperature )

Explanation:

°C = ( °F - 32 ) / 1.8
°F = ( 1.8 * °C ) +32

a) 95°F ⇒ °C = ( 95 - 32 ) / 1.8 = 35°C

b) 12°F ⇒ °C = ( 12 - 32 ) / 1.8 = -11.11°C

c) 102°F ⇒ °C = ( 102 -32 ) / 1.8 = 38.88°C

d) 1852°F ⇒ °C = ( 1852 -32 ) / 1.8 = 1011.11°C

e) 273.15°C ⇒ °F = ( 1.8 * 273.15 ) + 32 = 523.67°F

4 0

3 years ago

What is the percent composition of N H S O in (NH4)2SO4

Lena [83]

Answer:

The percent composition is 21% N, 6% H, 24% S and 49% O.

Explanation:

1st) The molar mass of (NH4)2SO4 is 132g/mol, and it represents the 100% of the mass composition.

In 1 mole of (NH4)2SO4, there are:

- 2 moles of N.

- 8 moles of H.

- 1 mole of S.

- 4 moles of O.

2nd) It is necessary to calculate the mass of each element, multiplying its molar mass by the number of moles:

- 2 moles of N (14g/mol) = 28g

- 8 moles of H (1g/mol) = 8g

- 1 mole of S (32g/mol) = 32g

- 4 moles of O (16g/mol) = 64g

3rd) With a mathematical rule of three we can calculate the percent composition of each element in the molecule of (NH4)2SO4:

$\begin{gathered} \text{ Nitrogen:} \\ 132g-100\% \\ 28g-x=\frac{28g*100\%}{132g} \\ x=21\% \end{gathered}$ $\begin{gathered} \text{ Hydrogen:} \\ 132g-100\operatorname{\%} \\ 8g-x=\frac{8g*100\operatorname{\%}}{132g} \\ x=6\% \end{gathered}$ $\begin{gathered} \text{ Sulfur:} \\ 132g-100\operatorname{\%} \\ 32g-x=\frac{32g*100\operatorname{\%}}{132g} \\ x=24\% \end{gathered}$ $\begin{gathered} \text{ Oxygen:} \\ 100\%-21\%-6\%-24\%=49\% \\ \\ \end{gathered}$

In this case, we can calculate the percent composition of Oxygen by subtracting the other percentages, since the total must be 100%.

So, the percent composition is 21% N, 6% H, 24% S and 49% O.

8 0

1 year ago

According to Newton's Third Law, If one object exerts a force on a second object, the second object exerts a force on the first

blagie [28]

Equal in magnitude and opposite in direction.

3 0

3 years ago

Which product of prime polynomials is equivalent to 36x3 – 15x2 – 6x?

monitta

The product of prime polynomials is equivalent to 36x3 – 15x2 – 6x is letter B which is 3x(3x – 2)(4x 1). Below is the solution.

3x(3x - 2) (4x + 1)
= 9x2 - 6x (4x + 1)
= 36x3 + 9x2 + - 24x2 - 6x
= 36x3 - 15x2 - 6x

3 0

3 years ago

Read 2 more answers

Which atoms in the pair has the larger atomic radius ? Help please !!

Ne4ueva [31]

A

1. Potassium, K.

2. Calcium, Ca.

3. Gallium, Ga.

4. Carbon, C.

5. Bromine, Br.

6. Barium, Ba.

7. Silicon, Si.

Explanation:

4 0

2 years ago

Read 2 more answers