Answer:
6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.
Explanation:
![Rate = k[AB]^2](https://tex.z-dn.net/?f=Rate%20%3D%20k%5BAB%5D%5E2)
The order of the reaction is 2.
Integrated rate law for second order kinetic is:
![\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA_t%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B%5BA%5D_0%7D%2Bkt)
Where, ![[A_0]](https://tex.z-dn.net/?f=%5BA_0%5D)
is the initial concentration = 1.50 mol/L
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the final concentration = 1/3 of initial concentration = 
= 0.5 mol/L
Rate constant, k = 0.2 L/mol*s
Applying in the above equation as:-
<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>
They will become unequivalent
Physical properties- color, density, solubility.
<span>Chemical property- odor.
</span>You see, a physical property<span> is any property that can be </span>measured<span> , and a one that </span><span>describes the state of the physical system.
</span>
https://socratic.org/questions/are-properties-such-as-odor-color-density-and-solubility-physical-or-...
Explanation:
from the equation 1 mole of O2 will give 2 moles of H2O then 6.0 moles of O2 will give x
6.0*2 moles/ 1 mole
= 12 moles
this implies that, 6.0 moles of O2 will give = 12 moles of water
Answer:
Yes, given statement is true.
Explanation:
Given that a cylinder of 1000 ml is marked at every 100 ml.
During the test, the student can easily check the volume of liquid so the student's guess is 750 ml true.
With this measurement, we can estimate that 1/10th of 100 ml can be measured.
So, given statement is correct.
