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For the given reactions determine if the entropy increases or decreases.

Alex73 [517]

Entropy increases in reaction 1 due to increase in the number of particles while entropy decreases in reaction 2 due to decrease in the number of particles.

Entropy refers to the degree of disorderliness in a system. The higher the entropy, the more disorderly the system is and the lower the entropy, the less disorderly the system is. We must note that entropy increases with increase in the number of particles.

In the reaction, 2 KClO3 (s)⇌2 KCl (s)+3 O2 (g), entropy increases because one of the products is a gas and the number of particles increases from left to right. In the second reaction, CoCl2 (s)+6 H2O (g)⇌CoCl2⋅6H2O, entropy decreases because the number of particles decreases.

Learn more: brainly.com/question/14281129

3 0

3 years ago

A sample weighing 3.110 g is a mixture of Fe 2 O 3 (molar mass = 159.69 g/mol) and Al 2 O 3 (molar mass = 101.96 g/mol). When he

grandymaker [24]

Answer:

The mass fraction of ferric oxide in the original sample : $\frac{723}{3110}$

Explanation:

Mass of the mixture = 3.110 g

Mass of $Fe_2O_3=x$

Mass of $Al_2O_3=y$

After heating the mixture it allowed to react with hydrogen gas in which all the ferric oxide reacted to form metallic iron and water vapors where as aluminum oxide did not react.

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

Mass of mixture left after all the ferric oxide has reacted = 2.387 g

Mass of mixture left after all the ferric oxide has reacted = y

$x=3.110 g- y=3.110 g - 2.387 g = 0.723 g$

The mass fraction of ferric oxide in the original sample :

$\frac{0.723 g}{3.110 g}=\frac{723}{3110}$

5 0

3 years ago

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The

AysviL [449]

Answer:- Heat lost by the metal is 279.45 cal.

Solution:- This type of problems are solved by using the concept, heat given = - heat taken

Metal temperature is decreasing from 45.00 degree C to 11.08 degree C. It means the heat is lost by the metal and this heat lost by metal is gained by water and the calorimeter to raise their temperature.

the equation we use is, $q=mc\Delta T$ .

where, q is the heat energy, m is mass, c is specific heat and $\Delta T$ is change in temperature.

Combined mass of calorimeter and water is 250.0 g and the specific heat is $\frac{1.035cal}{g.^0C}$ .

$\Delta T$ for calorimeter and water (combined) = 11.08 - 10.00 = 1.08 degree C

$\Delta T$ for metal = 11.08 - 45.00 = -33.92 degree C

let's plug in the values in the above equation and calculate heat gained by combined system.

q=250.0g*\frac{1.035cal}{g.^0C}*1.08^0C

q = 279.45 cal

So, the heat lost by the metal is 279.45 cal.

3 0

4 years ago

Read 2 more answers

You've just solved a problem and the answer is the mass of an electron, me=9.11×10−31kilograms. How would you enter this number

mihalych1998 [28]

The mass of an electron can be expressed in the box as $\boxed{{m_e} = 9.1 \times {{10}^{ - 31}}{\text{ kg}}}$ .

Further explanation:

Atom is the smallest particle that can be present in any element. It is also known as the building unit of matter. Each atom has a central part that is known as the atomic nucleus. There are three subatomic particles that constitute the atom. These particles are protons, neutrons, and electrons. The atomic nucleus consists of protons and neutrons, both are collectively called nucleons. Electrons revolve around the nucleus of an atom in definite orbits.

Protons are positively charged subatomic particles, electrons are negatively charged and neutrons have no charge. Since electrons carry a unit negative charge, these create an electric field around them. These also participate in nuclear reactions. The mass of an electron $\left( {{m_e}} \right)$ is $9.1 \times {10^{ - 31}}{\text{ kg}}$ , that of protons is $1.6726219 \times {10^{ - 27}}{\text{ kg}}$ and that of neutrons is $1.674927471 \times {10^{ - 27}}{\text{ kg}}$ . The electrons are responsible for chemical properties of elements. The distribution and arrangement of electrons is used to predict whether the element will be inert or reactive.

Therefore the required answer is $\boxed{{m_e} = 9.1 \times {{10}^{ - 31}}{\text{ kg}}}$ .

Learn more:

Component of John Dalton’s atomic theory: brainly.com/question/2357175
Basis of investigation for the scientists: brainly.com/question/158048

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Atomic structure

Keywords: atom, matter, atomic nucleus, proton, electron, neutron, subatomic particle, nuclear reactions, electric field, reactive, inert.

4 0

4 years ago

What is the OH- concentration of a solution whose pH is 12.40?

Elanso [62]

PH + pOH = pKw = 14

12.40 + pOH = 14

pOH = 14 - 12.40

pOH = 1.6

[OH⁻] = $10 ^{-pOH}$

[OH⁻] = $10 ^{-1.6}$

[OH⁻] = 2.5x10⁻² M

hope this helps!

7 0

3 years ago