Can someone help me with this circle geometry problem (question 1) ty
1 answer:
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The value of x is 15.
Solution:
Given ΔPQR ΔUTV.
<em>If two triangles are similar, then the corresponding parts are congruent.</em>
Do cross multiplication, we get
⇒ 14(x - 3) = 8(x + 6)
⇒ 14x - 42 = 8x + 48
Add 42 on both sides.
⇒ 14x = 8x + 90
Subtract 8x on both sides.
⇒ 6x = 90
Divide by 6 on both sides.
⇒ x = 15
The value of x is 15.