So we know that 1 inch on the map = 5 inches.
So if Brady's house is 23 inches away from Flagstaff on the map:
23 * 5 = 115.
So 115 inches is the actual distance...
Wait. His house is 9 feet away from Flagstaff? That's cool.
Answer:
n= 11.65 years
Step-by-step explanation:
Giving the following information:
Present Value (PV)= $33,000
Future Value (FV)= $15,000
Decrease rate (d)= 7%
<u>To calculate the number of years it will take to reach $15,000; we need to use the following formula:</u>
<u></u>
n= ln(FV/PV) / ln(1+d)
n= ln(15,000/33,000) / ln(1.07)
n= 11.65 years
the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
no
Step-by-step explanation:
the x value (-1) repeats therefore it ain't a function
