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kvasek [131]
2 years ago
5

Find the value of x and y. Show all your work neat and in order.

Mathematics
1 answer:
Mazyrski [523]2 years ago
8 0

Answer:

x = 21°

y = 29°

Step-by-step explanation:

a) Solving for x

Note that:

(3x - 3)° and 60° are Alternate interior angles, and alternate interior angles are equal to each other, hence:

3x - 3 = 60° (Alternate interior angles)

Add 3 to both sides

3x - 3 +3 = 60 + 3

3x = 63°

x = 63°/3

x = 21°

b) Solving for y

Notes that:

(3x - 3)° and (4y + 4)° are Consecutive interior angles and the sum consecutive interior angles is 180°

3x - 3 + 4y + 4 = 180°

3x + 4y - 3 + 4 = 180°

3x + 4y + 1 = 180°

Note that x = 21

Hence

3(21) + 4y + 1 = 180°

63 + 1 + 4y = 180°

64 + 4y = 180°

Subtract 64 from both sides

64 - 64 + 4y = 180° - 64

4y = 116°

y = 116/4

y => 29°

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Read 2 more answers
an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor
Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>

<u />

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • The Z-score measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u> </u>

<u />

In this problem:

  • Mean of 8.8 inches, thus \mu = 8.8.
  • Standard deviation of 2.8 inches, thus \sigma = 2.8.

<u />

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

<u />

25th percentile:

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Z = \frac{X - \mu}{\sigma}

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X - 8.8 = -0.675(2.8)

X = 6.91

75th percentile:

  • X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 8.8}{2.8}

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IQR = 10.69 - 6.91 = 3.78

What is the diameter, in inches, of the smallest tree that is an outlier?

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10.69 + 1.5(3.78) = 16.36

The diameter of the smallest tree that is an outlier is of 16.36 inches.

<u />

A similar problem is given at brainly.com/question/15683591

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Answer:

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Step-by-step explanation:

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2 years ago
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