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Stolb23 [73]
3 years ago
14

Please help me with my math homework. I don’t understand it

Mathematics
1 answer:
Feliz [49]3 years ago
6 0

Expert Checked

Me too there's no math problem...

Things you could try to fix this:

Try asking your teacher what is the work?

Try searching or contacting main educator on your work files.

Figure out what your teacher told you

Try calling the school or teacher.

Etc.

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lilavasa [31]

if we have a number like say hmm 4, and we say hmmm √4 is ±2, it simply means, that if we multiply that number twice by itself, we get what's inside the root, we get the 4, so (+2)(+2) = 4, and (-2)(-2) = 4, recall that <u>minus times minus = plus</u>.

so, any when we're referring to even roots like \bf \sqrt[2]{~~},\sqrt[4]{~~},\sqrt[6]{~~}...., the positive number, that can multiply itself an even amount of times, will produce a valid value, BUT the negative number that multiply itself an even amount of times, will also produce a valid value.

now, that's is not true for odd roots like \bf \sqrt[3]{~~},\sqrt[5]{~~},\sqrt[7]{~~}...., because the multiplication of the negative number will not produce a valid value, let's put two examples on that.


\bf \sqrt[3]{27}\implies \sqrt[3]{3^3}\implies 3\qquad because\qquad (3)(3)(3)=27&#10;\\\\\\&#10;however\qquad (-3)(-3)(-3)\ne 27~\hspace{8em}(-3)(-3)(-3)=-27&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\sqrt[3]{-125}\implies \sqrt[3]{-5^3}\implies -5\qquad because\qquad (-5)(-5)(-5)=-125&#10;\\\\\\&#10;however\qquad (5)(5)(5)\ne -125~\hspace{10em}(5)(5)(5)=125


so, when the root is an odd root, you will always get only one number that will produce the radicand.

6 0
3 years ago
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