PLS HELP!!!!! I WILL GIVE BRAINLY

Now evaluate. Substitute −2 for x in the composition f(g(x)) = 4x6 + 4x3 + 1, then simplify. f(g(−2)) =

Viktor [21]

F(g(-2))=4(-2)^6+4(-2)^3+1
f(g(-2))=4(64)+4(-8)+1
f(g(-2))=256-32+1
f(g(-2))=224+1
f(g(-2))=225

4 0

4 years ago

READ the question and choose an answer below. You may look at the maps in Resources for Chapter 9, Lesson 1 and or you may use t

disa [49]

The answer is is Afghanistan

4 0

3 years ago

Assume that foot lengths of women are normally distributed with a mean of 9.6 in and a standard deviation of 0.5 in.a. Find the

Makovka662 [10]

Answer:

a) 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b) 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c) 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 9.6, \sigma = 0.5$ .

a. Find the probability that a randomly selected woman has a foot length less than 10.0 in

This probability is the pvalue of Z when $X = 10$ .

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{10 - 9.6}{0.5}$

$Z = 0.8$

$Z = 0.8$ has a pvalue of 0.7881.

So there is a 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b. Find the probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

This is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 8.

When X = 10, Z has a pvalue of 0.7881.

For X = 8:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{8 - 9.6}{0.5}$

$Z = -3.2$

$Z = -3.2$ has a pvalue of 0.0007.

So there is a 0.7881 - 0.0007 = 0.7874 = 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c. Find the probability that 25 women have foot lengths with a mean greater than 9.8 in.

Now we have $n = 25, s = \frac{0.5}{\sqrt{25}} = 0.1$ .

This probability is 1 subtracted by the pvalue of Z when $X = 9.8$ . So:

$Z = \frac{X - \mu}{s}$

$Z = \frac{9.8 - 9.6}{0.1}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772.

There is a 1-0.9772 = 0.0228 = 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

5 0

4 years ago

Z varies jointly with y and the square of x. If x=4 when y=−7 and z=−336, find x when z=36 and y=3.

mario62 [17]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\$

$\bf \textit{z varies jointly with y and the square of x}\qquad z=kyx^2
\\\\\\
\textit{we also know that }
\begin{cases}
x=4\\
y=-7\\
z=-336
\end{cases}\implies -336=k(-7)(4)
\\\\\\
\cfrac{-336}{-28}=k\implies 12=k\qquad \qquad \boxed{z=12yx^2}
\\\\\\
\textit{when z=36 and y=3, what is \underline{x}?}\qquad 36=12(3)x^2
\\\\\\
\cfrac{36}{12\cdot 3}=x^2\implies \sqrt{\cfrac{36}{12\cdot 3}}=x$

6 0

3 years ago

Read 2 more answers

Find the missing angle measures <br><br><br> Helppp por favor!!

madam [21]

Angle: 180-132 = 48
180-48= 132
132/6=22

2(22)= 44
4(22)= 88

44+88+32 = 180

Answer:
Measure of angle < CBA = 88

Measure of angle < BCA = 44

6 0

3 years ago