<h3>
Answer: RJ = 10</h3>
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Explanation:
Recall that midsegments are half as long as the side they are parallel to. In this case, midsegment PQ is parallel to segment GJ. This means PQ is half as long as GJ. Phrased another way, we can say GJ is twice as long as PQ.
So,
GJ = 2*PQ
Also, we can see that GR = RJ due to the triple tickmarks they share. This leads to GJ = GR+RJ = RJ+RJ = 2*RJ
Or in short,
GJ = 2*RJ
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In summary we can see that
equating both right hand sides leads to
2RJ = 2PQ
RJ = PQ
Because PQ is 10 units, this means RJ is also 10 units.
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Another way to see why PQ = RJ is to notice how triangles HPQ and QRJ are congruent triangles (use SAS to prove this). The corresponding pieces PQ and RJ are the same length, so PQ = RJ = 10.
6+3x = 2(2) + 2(x)
6+3x = 4 + 2x
-6 -6
3x = -2+2x
-2x -2x
answer:
x = -2
Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Use desmos.com and graph those inequalities. It is pretty easy.
Answer:
Thirteen hundredth
Step-by-step explanation:
