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KiRa [710]
2 years ago
7

Help me pls the photo attached is the question quick pls ill give brainliest answer​

Mathematics
2 answers:
andriy [413]2 years ago
5 0

Answer:

12:18 and 20:30

Step-by-step explanation:

Naya [18.7K]2 years ago
5 0

Answer:

12:18? n 20:30?

Step-by-step explanation:

sorry if im rong

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LAST ONE! Simplify the following expression.
ELEN [110]

Answer:

5+5root3

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Applying properties of Exponents in exercise,use the properties of exponents to simplify the expression.See example 1.
evablogger [386]

Answer: a) 15625, b) 0.2, c) 625, d) 0.008.

Step-by-step explanation:

Since we have given that

a) (5^2)(5^3)

As we know that

a^m\times a^n=a^{m+n}

So, it becomes,

5^2\times 5^3=5^{2+3}=5^6=15625

(b) (5^2)(5^{-3})

So, it becomes,

5^2\times 5^{-3}=5^{2-3}=5^{-1}=\dfrac{1}{5}=0.2

(c) (5^2)^2

As we know that

(a^m)^n=a^{mn}

So, it becomes,

5^{2\times 2}=5^4=625

(d) 5^{-3}

a^{-m}=\dfrac{1}{a^m}\\\\5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}=0.008

Hence, a) 15625, b) 0.2, c) 625, d) 0.008.

4 0
3 years ago
John wants to send a letter to peter who lives on tesla street john does not remember the house number however he knows that it
Serggg [28]

Answer: 137 letters.

Step-by-step explanation:

The data is:

The number has 4 digits.

The number is a multiple of 5

The number is a multiple of 7

The last digit is a 0.

Then, let's find all the possible numbers that met these conditions.

Our number can be formed with 4 digits, A, B, C and D.

D is the last one, so we have  D = 0.

So the number is: ABC0

We know that all the numbers that end with 0 are multiples of 5, so that condition does not matter.

Now, a number is divisible by 7 if:

Take the last digit of the number, double it and subtract it to the remaining number, if the result is multiple of 7, then the initial number is a multiple of 7.

In this case the last digit is 0, so when we double it and subtract it, we actually are not changing the other 3 digits.

Then we have that:

ABC must be a multiple of 7.

So now our problem reduces to find the number of 3-digit numbers that are multiples of 7.

The first multiple of 7 that has 3 digits is:

7*15 = 105.

And the largest possible 3 digit number is 999, now let's try to divide it by 7 to see if this is also a multiple of 7.

999/7 = 142.7

the quotient is not integer, so 999 is not a multiple of 7.

The next option is 998, we can do the same here:

998/7 = 142.6

And so on, we will find that the largest 3 digit multiple of 7 is:

994, such that:

7*152=994.

Then we have:

Smallest: 7*15 = 105

Largest: 7*152 = 994.

Then the number of multiples of 7 between 999 and 100 will be equal to the difference between the quotients between the multples and 7.

105/7 = 15

994/7 = 152

152 - 15 =  137

So we have 137 multiples of 7 with 3 digits.

Then we have 137 4-digit numbers, that end with a zero and also are divisible by 5 and 7.

So John must send 137 letters if he wants to be shure that Peter will get the card.

5 0
3 years ago
Question<br> Determine the number of solutions to the quadratic equation: 572 + 62 – 2 = 0.
love history [14]

We know: 572 + 62 – 2 ≠ 0

So there is no solution the quadratic equation: 572 + 62 – 2 = 0

ok done. Thank to me :>

5 0
2 years ago
the game stop is having a sale and all games are reduced by 55%. if a game is now 29.99, what was the original price
Natali5045456 [20]
<span>54.5272727 hope this helps
</span>
3 0
3 years ago
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