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Allushta [10]
2 years ago
13

Can you guys help me answer it

Mathematics
1 answer:
Hitman42 [59]2 years ago
8 0

Answer:

300pi

Step-by-step explanation:

that is 3/4 of a circle with the radius of 20. Meaning that the area is 300pi

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It would be 60cm because 40 plus 20 equals 60
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The cost of a pearl $C is directly proportional to the square of its mass , m grams. given that a pearl of mass 10g cost $240
yulyashka [42]

Step-by-step explanation:

doing with the ratio method

25 x

10 240

x=25×240÷10

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Find the volume of the cylinder if the diameter is 6 inches and the height is three times the radius. Round your answer to the n
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7 0
3 years ago
Ajay reads aloud from a sports magazine. He comes across the measurement 0.63 kilometer. How should he read this measurement alo
Mashutka [201]

Answer:

"sixty-three hundredths of a Kilometer"

Step-by-step explanation:

Decimal measurements are read based on the place of their digits. In this case, Ajay would read this measurement as "sixty-three hundredths of a Kilometer". This is because the final digit of the decimal form measurement is in the "hundredths" position. One more to the right and it would be in the "thousandths" while one more to the left would be the "tenths"

4 0
3 years ago
Use the laplace transform to solve the given initial-value problem. y'' − 8y' 16y = t, y(0) = 0, y'(0) = 1
fgiga [73]

If the initial value problem is y^{11} -8y^{1} -15y=0 and y^{1}(0) =1,y(0)=0 then y(t)=(e^{3t} -e^{5t} )/2.

Given the initial value problem be   y^{11} -8y^{1} -15y=0and  y^{1}(0) =1,y(0)=0.

We are required to find the solution of the given initial value problem.

Laplace transform is an integral transformation that converts a function of a real variable to a function of a complex variable.

Take laplace on the DE, we get

s^{2}-sY(0)-y^{i}(0)-8[sY(s)-y(0)-15Y(s)]=0

s^{2}Y(s)-s(0)-1-8{sY(s)-0)}+15Y(s)=0

(Putting the values given in question)

Y(s)=(s^{2} -8s+15)-1=0

Y(s)=1/(s^{2} -8s+15)

Simplifying the above:

=1/(s^{2} -5s-3s+15)

=1/[s(s-5)-3(s-5)]

=1/2 [1/(s-3)-1/(s-5)]

Taking inverse of the above we get,

y(t)=(e^{3t} -e^{5t} )/2

Hence if the initial value problem is y^{11} -8y^{1} -15y=0 and y^{1}(0) =1,y(0)=0 then y(t)=(e^{3t} -e^{5t} )/2.

Learn more about laplace transform at brainly.com/question/17062586

#SPJ1

                               

7 0
2 years ago
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