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2 years ago

Round 27834 to 2 significant figures

Mathematics

1 answer:

julsineya [31]2 years ago

5 0

28000 is the answer.

you count two numbers from front and approximate

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HELP! will mark BRAINILEST !

Sedbober [7]

I like A as the best one

420 = 100*price - (fixed costs)
220 = 60*price - (fixed costs)

If we subtract one from the other one, we get 200 = 40*price, price = 5
that said, fixed costs are 500 - 420 = 80

Now if we move -220 to the right in Answer A, we'll get:

y = 5x -300 + 220 = 5x - 80

So it looks like A describes the model best

6 0

2 years ago

Find the sum of 7a³ + 14a + 12 and -6a³ + 12a² -7

maw [93]

Answer: $a^3+12a^2+14a+5$

Step-by-step explanation:

$7a^3+14a+12+(-6a^3+12a^2-7)$

$7a^3+14a+12-6a^3+12a^2-7\\a^3+12a^2+14a+5$

7 0

2 years ago

A shirt that normally costs 30 dollers s on sale for 21.75 what percent of the regular price is the sale price

ivanzaharov [21]

72.5%

You can get this by dividing the new price by the original price and then multiplying by 100.

3 0

3 years ago

Test the series for convergence or divergence (using ratio test)

Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

Step(i):-

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

Step(ii):-

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

= $= \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }$

$=\frac{1}{infinite }$

$\lim_{n \to \infty} U_n =0$

∴ Given series is converges

3 0

2 years ago

In a circle with a radius of 7 feet, the radian measure of the central angle subtended by an arc with a length of 4 feet is . Th

ivann1987 [24]

We know that
length of a sector=[∅]*r--------> when ∅ is in radians
so
∅=length of a sector/r
for r=7 ft
length of a sector=4 ft
∅=4/7-----> 0.57 radians

the answer part 1) is 0.57 radians

part 2)
area of a sector=(∅/2)*r²--------> when ∅ is in radians
area of a sector=(4/7/2)*7²-----> (4/14)*49----> 14 ft²

the answer Part 2) is 14 ft²

3 0

3 years ago