Answer:
wish I could help but I don't understand it ,so maybe someone can come and help u
Answer:
You see the concentration decreased ten fold, from 1 M to 0.1 M.
You can simply increase the volume by ten times.
For example
If you have 250 mL of 1 molar HCl, you can add distilled water upto 2500 mL. Now the concentration is 0.1 molar.
If you want to use the serial dilution method, you can use the C1V1=C2V2 equation.
C1 = starting concentration.
C2 = final concentration.
V is for volume.
So let's say you have 500 mL of 1 M HCl and you only want 50 mL of 0.1 M HCl.
1 M x V1 = 0.1 M x 50 mL
V1 = 5 mL
So you take 5 mL of the original (stock) solution and dilute it up to 50 mL. Then you have 50 mL of 0.1 M HCl.
Explanation:
Answer:
pH = 10
Explanation:
KOH is a strong base; thus it will completely dissociate:
KOH -> K⁺ + OH⁻
Since it completely dissociates, the concentration of both K⁺ and OH⁻ will be the concentration of KOH given (1.0 x 10^-4 M).
We can then find pOH by taking the negative log of the OH⁻, or hydroxide, concentration:
pOH = -log[OH⁻] = -log[1.0 x 10^-4 M] = 4
At 25 degrees Celsius, pH + pOH = 14. If we solve for pH and then plug in our pOH, we get:
pH = 14 - pOH = 14 - 4 = 10
The pH of a 1.0 x 10^-4 M solution of KOH is thus 10.
Answer: 60.7 g of will be formed.
Explanation:
To calculate the moles :
The balanced chemical reaction is
is the limiting reagent as it limits the formation of product and is the excess reagent.
According to stoichiometry :
6 moles of produce = 4 moles of
Thus 2.68 moles of will produce= of
Mass of
Thus 60.7 g of will be formed by reactiong 60 L of hydrogen gas with an excess of
Answer:
hey, it's B
Explanation:
1 mol= 6.022×10²³ ions
0.2 mol= 0.2 × 6.022 × 10²³ ions