Question

You need to prepare 250. mL of a 0.300 M aqueous solution of sucrose, C12H22O11 (aq), which is used frequently in biological experiments.Based on your answer above, what is the value of x?

Answer 1

The question is incomplete, here is the complete question:

You need to prepare 250. mL of a 0.300 M aqueous solution of sucrose, $C_{12}H_{22}O_{11}$ (aq), which is used frequently in biological experiments. Based on your answer above, measure out the amount of solid sucrose in the solution.

Answer: The mass of solid sucrose present in the solution is 25.7 grams.

Explanation:

To calculate the mass of sucrose, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Molarity of solution = 0.300 M

Molar mass of sucrose = 342.3 g/mol

Volume of solution = 250. mL

Putting values in above equation, we get:

$0.300mol/L=\frac{\text{Mass of sucrose}\times 1000}{342.3g/mol\times 250.}\\\\\text{Mass of sucrose}=\frac{0.300\times 342.3\times 250.}{1000}=25.7g$

Hence, the mass of solid sucrose present in the solution is 25.7 grams.