Anwser
For general projectile motion with no air resistance, the horizontal component of a projectile's velocity ... D. first decreases and then increases ... E. The speed of the object is constant but its velocity is not constant. C ... Neglecting air resistance, when the package hits the ground
Explanation:
Answer:
8.87 m/s^2
Is the same for both planets
Explanation:
Hello!
The surface gravity can be calculated from Newton's Law of Gravitation and Newton's Second Law :
ma = F =G Mm/r^2
Solving for a:
a = G M/r^2
And the surface graity g = a(R), that is, the surface gravity is equal to the acceleration evaluated at the radius of the planet:
g = G M/R^2
Since G is a constant, we need to evaluate M/R^2 for both to know in which planet the surface gravity is the geratest:
M_u/R_u^2 = 1.323 x 10^11 kg/m^2
M_v/R_v^2 = 1.323 x 10^11 kg/m^2
It turns out that the surface gravity in both planets is the same! which is:
g = G M_u/R_u^2
= ( 6.67408 × 10-11 m^3 / (kg s^2) ) *( 1.323 x 10^11 kg/m^2)
= 8.87 m/s^2
*as you can check on google*
You would feel the same weigth in both planets, however you wil feel lighter in these planets than in earth.
I think it’s B I could be wrong but I tried lol
Answer:
La aceleración total de la piedra es 2,85 m/s².
Explanation:
La aceleracion total de la piedra viene dado por la suma de la acelaración centrípeta y de aceleración tangencial, como:
La aceleración tangencial () es la aceleracion del cilindro igua a:
Entonces, la aceleración centrípeta es:
En donde:
v: es la velocidad tangencial de la piedra = 2,0 m/s
r: es el radio del cilindro = 1,5 m
Finalmente, el módulo de la aceleración total es:
Por lo tanto la aceleración total de la piedra es 2,85 m/s².
Espero que te sea de utilidad!