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Arisa [49]
2 years ago
13

Psychology:

Physics
2 answers:
Bas_tet [7]2 years ago
5 0

Answer:

False is correct

Explanation:

Peace and Love

mestny [16]2 years ago
4 0

Answer:

thank you

Explanation:

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sladkih [1.3K]
<span>The relationship between wavelength, frequency and energy of Electromagnetic Radiation is given by E = hf = hc/lamba -------(1) So from (1) there's a linear relationship between E and f. The higher the frequency, f, the higher the energy E. Also from (1) it is obvious that the lower the wavelength, lambda, the higher the energy, E. This means the answer is D.</span>
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2 years ago
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Which types of questions can most likely be answered through a scientific investigation?
Sindrei [870]

Subjective questions can be answered most likely through well-designed scientific investigations. Investigating peoples opinions or favorites does not involve any scientific investigations.

<h3>What are scientific investigation?</h3>

Scientific investigations include study on different natural phenomenon through well designed research methodologies. They include a preliminary hypothesis based on observations and various scientific records helps for reference.

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4 0
1 year ago
Which solid dissolves faster in water?<br><br> sugar cube<br> or<br> powdered sugar
Verdich [7]

Answer: <em>Powdered sugar</em>

Powdered sugar dissolves faster compare to the sugar cube. Because sugar cube has less surface area (the granules are tightly packed) compared to powdered sugar  

6 0
2 years ago
To navigate, a porpoise emits a sound wave that has a wavelength of 3.3 cm. The speed at which the wave travels in seawater is 1
dedylja [7]

Answer:

2.2\times 10^{-5} s

Explanation:

We are given that  

The wavelength of sound wave=\lambda=3.3 cm=3.3\times 10^{-2}m/s

1 cm/s=10^{-2}m/s

Speed of sound wave,v=1522 m/s

We have to find the period of the wave.

We know that

Frequency=\nu=\frac{v}{\lambda}

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Frequency =\frac{1522}{3.3\times 10^{-2}}=4.6\times 10^{4} Hz

Time period=\frac{1}{4.6\times 10^4}=0.22\times 10^{-4}\times \frac{10}{10^1}=2.2\times 10^{-4-1}=2.2\times 10^{-5}s

Using identity:\frac{a^x}{a^y}=a^{x-y}

Hence, the time period of the wave=2.2\times 10^{-5} s

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3 years ago
What is the uses of echoes​
Anestetic [448]

Answer:

Echoes are the reflection of sound from relatively flat object that is far enough away that you can discern the time difference. Echoes are used to measure distance, velocity, and the shape of objects. Echoes off gratings result in an unusual pinging sound

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