Answer:
Step-by-step explanation:
can be said as " divided by 
", so the ? is .
Answer:
x = 387
Step-by-step explanation:
The wind acts in the opposite direction to the plane when the time is longer.
The wind acts in the same direction as the plane when the time is shorter.
Equation
d = r*t
Givens
- d = 1720
- x = plane's speed
- y = wind speed
- t1 = 5 hours
- t2 = 4 hours.
Substitution
- d = (x + y) * t
- 1720 = (x + y) * 4
- 1720 = (x - y) * 5
Since the two distances are the same, you can equate the right hand sides.
- (x + y) * 4 = (x - y)*5 Remove the brackets.
- 4x + 4y = 5x - 5y Add 5y to both sides
- 4x + 4y + 5y = 5x - 5y + 5y Combine all the terms.
- 4x + 9y = 5x Subtract 4x from both sides
- 9y + 4x - 4x = 5x - 4x Combine
- 9y = x
Now use one of the given equations with the distance
- 1720 = (x + y)*4 Substitute 9y for x
- 1720 = (9y + y) * 4 Combine
- 1720 = 10y * 4 Multiply the right
- 1720 = 40y Divide by 40
- 1720/40 = 40y/40 Do the division
- 43 = y y = wind speek
- 9y = x x = 9*y
- 9*43 = x
- x = 387 miles per hour.
Answer:
y=2x-19
Step-by-step explanation:
I'm guessing you mean slope intercept form y=mx+b
If so, first you would have to find the slope of the line
To do that, use the formula y2-y1/x2-x1
Remember you can pick any coordinate pair for this
I will pick 1=y2 -5=y1 10=x2 and 7=x1
When I put that in the equation I get 1-(-5)/10-7
Overall I get 6/3, or 2
Now to find the y intercept, you plug in the slope and one of the coordinates(any is fine)
I will pick (10,1)
1=y and 10=x and 2=m
1=2(10)+b
this simplifies to 1=20+b
now subtract 20 from both sides and get -19 = b
Now you have your equation y=2x-19
Answer: 0.025
Step-by-step explanation:
Given : A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between the interval [48.0 minutes, 58.0 minutes].
The probability density function :-
Now, the probability that a given class period runs between 50.25 and 50.5 minutes is given by :-
![\int^{50.5}_{50.25}\ f(x)\ dx\\\\=\int^{50.5}_{50.25}\ \dfrac{1}{10}\ dx\\\\=\dfrac{1}{10}|x|^{50.5}_{50.25}\\\\=\dfrac{1}{10}\ [50.5-50.25]=\dfrac{1}{10}\times(0.25)=0.025](https://tex.z-dn.net/?f=%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20f%28x%29%5C%20dx%5C%5C%5C%5C%3D%5Cint%5E%7B50.5%7D_%7B50.25%7D%5C%20%5Cdfrac%7B1%7D%7B10%7D%5C%20dx%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%7Cx%7C%5E%7B50.5%7D_%7B50.25%7D%5C%5C%5C%5C%3D%5Cdfrac%7B1%7D%7B10%7D%5C%20%5B50.5-50.25%5D%3D%5Cdfrac%7B1%7D%7B10%7D%5Ctimes%280.25%29%3D0.025)
Hence, the probability that a given class period runs between 50.25 and 50.5 minutes =0.025
Similarly , the probability of selecting a class that runs between 50.25 and 50.5 minutes = 0.025
Answer:
20000000
Step-by-step explanation:
