Answer:
15 seconds
Step-by-step explanation:
If you make a table of values for the dog and the squirrel using d = rt, then the rates are easy: the dog's rate is 150 and the squirrel's is 100. The t is what we are looking for, so that's our unknown, and the distance is a bit tricky, but let's look at what we know: the dog is 200 feet behind the squirrel, so when the dog catches up to the squirrel, he has run some distance d plus the 200 feet to catch up. Since we don't know what d is, we will just call it d! Now it seems as though we have 2 unknowns which is a problem. However, if we solve both equations (the one for the dog and the one for the squirrel) for t, we can set them equal to each other. Here's the dog's equation:
d = rt
d+200 = 150t
And the squirrel's:
d = 100t
If we solve both for t and set them equal to each other we have:

Now we can cross multiply to solve for d:
150d = 100d + 20,000 and
50d = 20,000
d = 400
But we're not looking for the distance the squirrel traveled before the dog caught it, we are looking for how long it took. So sub that d value back into one of the equations we have solved for t and do the math:

That's 1/4 of a minute which is 15 seconds.
There are about 1241.4 miles of coast line in New Hampshire
<span>g(x) = x^3 - 9x^2 + 2x + 48 ?
Probe some roots. When you use x = - 2
you will have: (-2)^3 - 9(-2)^2 + 2(-2) + 48 = -8 - 36 - 4 + 48 = 0
So, - 2 is a root
From that you can divide x^3 - 9x^2 + 2x + 48 by x + 2 and you will get
x^2 - 11x + 24
Then you can factor that: (x - 8)(x - 3)
So, the three roots are x = - 2, x = 3 and x = 8, which is the option B.
Answer: option B. x = 8, x = -2 , and x = 3
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Hope this helps, comment if you have any questions:)))
Answer:
it increase by 31%
Step-by-step explanation:
1.31-1.00=.31 move the decimal place to the left 31%