Answer:
Part A - 8
Part B - 7
Step-by-step explanation:
Part A
She collected 8 gallons of syrup in total. Two gallons from first tree, three gallons from second tree and three gallons from third tree.
Part B
She used seven gallon of syrup for cooking.
She is left with one gallon syrup only out of total eight gallon syrup
Answer:
Rearrange the equation so "y" is on the left and everything else on the right.
Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).
Step-by-step explanation:
^^^
Let the width of the rectangle be W in.
Therefore, length = 2W in
Area of the rectangle, Ar = L*W = 2W*W = 2W^2
Also, perimeter of the rectangle, Pr = 2(L+W) = 2(2W+W) = 2(3W) = 6W
Then, perimeter of square, Ps = 52-6W
And, area of the square, As = [(52-6W)/4]^2 = [13-1.5W]^2 = (13-1.5W)(13-1.5W) = 169-19.5W-19.5W+2.25W^2 = 2.25W^2-39W+169
Therefore,
Total area, At = Ar+As = 2W^2+2.25W^2-39W+169 = 4.25W^2 -39W+169
For maximum area, the first derivative of the total area expression should be zero. Therefore;
dAt/dW = 8.5W - 39 = 0 => 8.5W = 39 => W = 39/8.5 = 4.588 in
Therefore, for maximum area, width (W) should be 4.588 in
Answer:
you need to read 11 or more books to pass your goal
Step-by-step explanation:
Coding the given algorithm in python 3, the <em>greatest</em> <em>common </em><em>divisor</em><em> </em>of the values (124 and 244) and (4424 and 2111) are 4 and 1 respectively.
The program implementation goes thus :
def gcd(a, b):
<em>#initialize a function named gcd which takes in two parameters</em>
if a>b:
<em>#checks if a is greater than b</em>
return gcd (b, a)
<em>#if true interchange the Parameters and Recall the function</em>
elif a == 0:
return b
elif a == 1:
return 1
elif((a%2 == 0)and(b%2==0)):
<em>#even numbers leave no remainder when divided by 2, checks if a and b are even</em>
return 2 * gcd(a/2, b/2)
elif((a%2 !=0) and (b%2==0)):
<em>#checks if a is odd and B is even</em>
return gcd(a, b/2)
else :
return gcd(a, b-a)
<em>A</em><em> </em><em>sample</em><em> </em><em>run</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>program</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>values</em><em> </em><em>given</em><em> </em><em>:</em>
print(gcd(124, 244))
print()
<em>#leaves a space after the first output</em>
print(gcd(4424, 2111))
Learn more :brainly.com/question/25506437