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1 year ago

What is the value of the expression when a = 6, b = 4, and c = 8? 2a3b−c

Mathematics

2 answers:

Novosadov [1.4K]1 year ago

6 0

Answer:

136

Step-by-step explanation:

(2*6*3*4)-8 = 144-8

= 136

devlian [24]1 year ago

4 0

Sksksjdnhwo9-9–928Oo

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Oduvanchick [21]

Answer:

No, this is not a function.

Step-by-step explanation:

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*Range - {2,5,2,4.8}

Rule: A function is a special type of relation in which each value of the domain is paired with exactly one value of the range.

Since 0 pairs with both 2 and 5, this would not be a function.

Hope this helps!

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GuDViN [60]

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2 years ago

The Apache Taxi Company charges $2.50 to pick up a passenger and then adds $1.95 per mile. Isaac was charged $27.46 to go from o

nirvana33 [79]

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2 years ago

Scientists have discovered a vaccine for a debilitating disease. This year there were 570,000 reported new cases of the disease

Ket [755]

Answer: There are approximately 853827 new cases in 6 years.

Step-by-step explanation:

Since we have given that

Initial population = 570000

Rate at which population decreases is given by

$\frac{2}{3}$

Now,

First year =570000

Second year is given by

$570000\times (\frac{1}{3})$

Third year is given by

$570000(\frac{1}{3})^2$

so, there is common ratio ,

it becomes geometric progression, as there is exponential decline.

so,

$570000,570000\times \frac{1}{3},570000\times( \frac{1}{3})^2,......,570000\times (\frac{1}{3})^6$

a=570000

common ratio is given by

$r=\frac{a_2}{a_1}=\frac{1}{3}$

number of terms = 6

Sum of terms will be given by

$S_n=\frac{a(1-r^n)}{(1-r)}$

We'll put this value in this formula,

$S_6=\frac{570000(1-(\frac{1}{3})^6}{(1-\frac{1}{3})}\\\\=853827.16$

So, there are approximately 853827 new cases in 6 years.

6 0

2 years ago