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Lynna [10]
3 years ago
15

The amount c in grams of a 100 gram sample of carbon-14 remaining after t years is represented by the equation c= 100 (0.99988)t

use a calculator to find the amount of carbon-14 remaining after 4 years
Mathematics
1 answer:
tigry1 [53]3 years ago
8 0

Answer: The amount of carbon-14 remaining after 4 years is 99.95 grams.

Step-by-step explanation:

Hi, to answer this question we simply have to substitute t=4 in the equation given and solve for c.

c= 100 (0.99988)^t

c =100 (0.99988)^4

c = 100 x 0.999520086

c= 99.95200864 ≅99.95 grams (rounded)

The amount of carbon-14 remaining after 4 years is 99.95 grams.

Feel free to ask for more if needed or if you did not understand something.

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Consider the probability that no less than 96 out of 145 people will not get the flu this winter. Assume the probability that a
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Answer:

0.1324 = 13.24% probability that no less than 96 out of 145 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

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The standard deviation of the binomial distribution is:

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Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 145, p = 0.61

So

\mu = E(X) = np = 145*0.61 = 88.45

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{145*0.61*0.39} = 5.87

Consider the probability that no less than 96 out of 145 people will not get the flu this winter.

More than 95 people, which is the same as 1 subtracted by the pvalue of Z when X = 95. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{95 - 88.45}{5.87}

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Z = 1.115 has a pvalue of 0.8676

1 - 0.8676 = 0.1324

0.1324 = 13.24% probability that no less than 96 out of 145 people will not get the flu this winter.

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Answer:

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The perimeter of a triangular window is 141 inches. The ratio of the side lengths of the window is 11:18:18. What are the side l
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The perimeter of a triangular window is the sum of its side lengths

The side lengths of the window are 33 inches, and 54 inches

<h3>How to determine the side lengths?</h3>

The ratio is given as:

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Rewrite as:

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