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marishachu [46]
3 years ago
5

....

Mathematics
1 answer:
Anna11 [10]3 years ago
3 0
<h2>Answer:</h2><h2>Plagiarism is when you take someones else's work and say it your own when its not. Without giving credit from your source that you used, that is considered plagiarism.</h2><h2 /><h2>Hope this helps!!</h2>

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Scorpion4ik [409]
Do 13,000x0.07=910 then do 910x4=3,640
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Find all possible values of theta if it is between
andrew11 [14]

See attached image for work.

5 0
2 years ago
Pls help me I will pick brainliest answer with tape diagram
NikAS [45]

Answer:

5mins- 300s

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5mins-3

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300/3=12600/x

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=126

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3 years ago
Patti ran the race in 8.4 minutes. Maisha ran it in 8.04 minutes. How does the value of 4 in Maisha's time compare with the valu
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6 0
3 years ago
Use the integral test to determine whether the series is convergent or divergent. [infinity] n = 2 n2 n3 + 1 Evaluate the follow
xxMikexx [17]

I think the given series is

\displaystyle\sum_{n=2}^\infty \frac{n^2}{n^3+1}

You can use the integral test because the summand is clearly positive and decreasing. Then

\displaystyle\sum_{n=2}^\infty\frac{n^2}{n^3+1} > \int_2^\infty\frac{x^2}{x^3+1}\,\mathrm dx

Substitute <em>u</em> = <em>x</em> ³ + 1 and d<em>u</em> = 3<em>x</em> ² d<em>x</em>, so the integral becomes

\displaystyle \int_2^\infty\frac{x^2}{x^3+1}\,\mathrm dx = \frac13\int_9^\infty\frac{\mathrm du}u = \frac13\ln(u)\bigg|_{u=9}^{u\to\infty}

As <em>u</em> approaches infinity, we have ln(<em>u</em>) also approaching infinity (whereas 1/3 ln(9) is finite), so the integral and hence the sum diverges.

5 0
3 years ago
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