Area of Trapezoid = (1/2) * (Sum of bases) * height
Area = (1/2) * (11 + 14) * 10
= (1/2) * 25 * 10 = 5 *25 = 125
Area = 125 m²
<em><u>Answer:</u></em>
Around 4 : 3 because the measurements might not be perfect.
<em><u>Step-by-step explanation:</u></em>
So the ratio of the NEW : ORIGINAL is just one side of the rectangle to the other side of the original one.
We know that the newer rectangle (or the larger one) has 4 cm as its side and that the original one (the smaller one) has 3cm as its side. Then we can create the ratio of NEW : ORIGINAL as: 4 : 3
<span>area of a square = a^2 = 5^2 = 25
answer
</span><span>area of a square = 25 cm^2</span>
Answer:
r =5 in
Step-by-step explanation:
Area of a circle is given by
A = pi r^2
We know the area and pi
78.5 = 3.14 r^2
Divide by 3.14
78.5/3.14 = 3.14 /3.14 r^2
25 = r^2
Take the square root of each side
sqrt(25) = sqrt(r^2)
5=r
Perpendicular from the center to the chord, bisects it!
DE = DF/2 = 12
To find R, use Pyth Th in triangle AOB. ( AB = 10)
10^2 + 14^2 = R^2
100+ 196 = 296 = R^2
In triangle DOE
x^2 + 12^2 = 296
x^2 = 296-144 = 152
x = √152
x = 12.3
