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BARSIC [14]
3 years ago
6

Patti ran the race in 8.4 minutes. Maisha ran it in 8.04 minutes. How does the value of 4 in Maisha's time compare with the valu

e of 4 in Patti's time?
Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

Answer:

Maisha ran the race in .36 seconds faster than Patti.

8.4 - 8.04 = .36

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Jonah runs 3/5 miles on Sunday and 7/10 miles on Monday.He uses the model to find that he ran a total of 1 mile. What mistake do
antoniya [11.8K]

Answer: He did not convert the fractions into the like fraction to add.


Step-by-step explanation:

Given: The distance Jonah runs on Sunday= \frac{3}{5} miles

The distance Jonah runs on Monday= \frac{7}{10} miles

The total distance he ran = \frac{3}{5}+\frac{7}{10}\ miles

Since both the fractions are not like , thus multiply 2 to the numerator and the denominator of the first fraction [to add fractions first convert them into like fractions], we get

The total distance he ran = \frac{3\times2}{5\times2}+\frac{7}{10}\ miles

=\frac{6}{10}+\frac{7}{10}=\frac{6+7}{10}\\\\=\frac{13}{10}=1\frac{3}{10}\ miles

The right answer is "The total distance he ran =1\frac{3}{10}\ miles"


7 0
3 years ago
Find the total surface area of this cuboid
Harman [31]

Step-by-step explanation:

☄ \underline{ \underline{ \sf{Given}}}:

  • Length ( l ) = 4 cm
  • Width ( w ) = 2 cm
  • Height ( h ) = 5 cm

☄ \underline{ \underline{ \sf{To \: find}}} :

  • Total surface area of a cuboid

❅\underline{ \underline{ \text{Solution}}}:

✑ \boxed{ \text{TSA = 2lw + 2lh + 2hw}}

Plug the known values :

⟼ \sf{2 \times 4 \times 2 + 2 \times 4 \times 5 + 2 \times 5 \times 2}

⟼ \sf{16 + 40 + 20}

⟼ \boxed{\sf{76 \:  {cm}}^{2} }

\red{ \boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : 76 \:  {cm}}^{2} }}}

Hope I helped !♡

Have a wonderful day / night ! ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

4 0
2 years ago
Hi can you guys help me. The topic is similiar shapes in this case triangles do you guys know how to find a length. I got some p
Airida [17]

PR=18mm
AB=7mm

All lengths of triangle PRQ are twice the lengths of ACB





4 0
3 years ago
The length of the midsegment of a triangle is always half the length of the side it is parallel to true or false
Vladimir [108]
True. The midsegment of a triangle is halfway up the triangle, and since the top half and the full triangle are similar triangles, its dimensions are proportional.

This means half the height will give half the base (midsegment). So the midsegment is always half the length of the side it's parallel to.
3 0
3 years ago
What is the value of y?
mojhsa [17]
<h2>QUESTION:- What is the value of y?</h2>

<h2>ANSWER:- </h2>

SUM OF ALL INTERIOR ANGLE = 180

y + y + 72 = 180 \\ 2y + 72 = 180 \\ 2y = 180 - 72 \\ 2y = 108 \\ y =  \frac{108}{2}  \\ y =  \frac{ \cancel{108}^{ \:  \:  \:  \tiny{54}}  }{ \cancel{2}}  \\ y = 54 \degree

4 0
3 years ago
Read 2 more answers
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