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2 years ago

13

Find all possible values of theta if it is between

1 answer:

andrew11 [14]2 years ago

5 0

See attached image for work.

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*!!!* please help me!! i’ll mark brainliest if the answer is right!

Margaret [11]

Answer

Roundworm is 9ft long and the tapeworm is 60 feet long

Step-by-step explanation:

If we turn this into an algebraic equation we get 8x-3=69 with 8x being x + 7x because we know that the tape worm is about 7 times longer than the round worm and the roundworms length would be x here. We have the -3 because it is 3 minus 7 times the total length. We do this and eventually end up with x = 9 which is the length of the roundworm. We multiply that by 7 to get 63 and subtract 3 to get 60. If you want to check if this is right do 60+9 and you'll get 69 which is the total of them end to end. (also 69 funny haha)

5 0

3 years ago

Is the following inequality always, sometimes, or never true? Why <br> 3+5x<5(x+1)

FrozenT [24]

It is never true because there is no sum

7 0

3 years ago

30 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! You have discovered another alien. Find the correct rescue path

elena-14-01-66 [18.8K]

Answer:

Answer: B. Y= 0x + 0

Step-by-step explanation: It's a straight line to the alienbecause it's straight down the x-axis

Hope this helped!

Step-by-step explanation:

Answer: B. Y= 0x + 0

Step-by-step explanation: It's a straight line to the alienbecause it's straight down the x-axis

Hope this helped!

3 0

4 years ago

Read 2 more answers

Which of the following statements are true? Select all that apply.

Tom [10]

Answer: The statements in options 2 and 4 are true.

Explanation:

The LCM of two numbers is the smallest number that is multiple of both numbers.

The factor of 8 and 12 are,

$8=2\times 2\times 2$

$12=2\times 2\times 3$

Since 2 and 2 are common in both but 2 and 3 are not same, therefore the L.C.M. of 8 and 12 is,

$L.C.M.(8,12)=2\times 2\times 2\times 3=24$

Therefore the statement in option 1 is incorrect.

The factor of 6 and 9 are,

$6=2\times 3$

$9=3\times 3$

Since 3 is common in both but 2 and 3 are not same, therefore the L.C.M. of 6 and 9 is,

$L.C.M.(6,9)=2\times 3\times 3=18$

Therefore the statement in option 2 is correct.

The factor of 11 and 4 are,

$11=1\times 11$

$4=2\times 2$

Since all factor are different, therefore the L.C.M. of 11 and 4 is,

$L.C.M.(11,4)=1\times 11\times 2\times 2=44$

Therefore the statement in option 3 is incorrect.

The factor of 9 and 10 are,

$9=1\times 9$

$10=2\times 5$

Since all factor are different, therefore the L.C.M. of 9 and 10 is,

$L.C.M.(9,10)=1\times 9\times 2\times 5=90$

Therefore the statement in option 4 is correct.

4 0

3 years ago

A researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 530 college students showed tha

otez555 [7]

Answer:

(0.1753 ; 0.2447)

Step-by-step explanation:

Using the relation :

Confidence interval :

p ± margin of error

p = 0.21

1 - p = 0.79

n = 530

Zcritical at 95% confidence level = 1.96

Margin of Error : Zcritical * sqrt[(p(1-p))/n]

1.96 * sqrt[(0.21(0.79))/530]

1.96 * 0.0176923 = 0.0346769

Margin of Error = 0.0346769

Lower boundary = 0.21 - 0.0347 = 0.1753

Upper boundary = 0.21 + 0.0347 = 0.2447

Confidence interval :

(0.1753 ; 0.2447)

5 0

3 years ago