The difference between the roots of the quadratic equation x2 -14x +q =0 is 6. Find q
1 answer:
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Answer:
q = 40
Step-by-step explanation:
When the quadratic has roots p and r, it can be factored as ...
(x -p)(x -r) = x² -(p+r)x +pr
So, the sum of the roots is 14, and their difference is 6. This lets us find the roots from ...
p + r = 14
p - r = 6
2p = 20 . . . add the two equations
p = 10
r = 14 -p = 4
The value of interest is then ...
q = pr = (10)(4)
q = 40
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The graph shows the roots to be 4 and 10, as we found.
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Answer:
The points for the given two linear equation as
= - 2 , - 6
= - 2 , 6
The graph so plotted as shown
Step-by-step explanation:
Given as :
The two linear equation are
y = 3 x ........A and
y = - x - 8 .........B
Solving equation A and B
Now, Put The value of y from eq A into eq B
So, 3 x = - x - 8
Or, 3 x + x = - 8
Or, 4 x = - 8
∴ x =
I.e x = - 2
Now , Put the value of x into eq A
∵ y = 3 x
∴ y = 3 × (-2)
I.e y = - 6
Again, Put the value of x into eq B
∵ y = - x - 8
∴ y = - 2 - (-8)
I.e y = 6
So, for x = - 2 , y = - 6
And for x = - 2 , y = 6
Hence , The points for the given two linear equation as
= - 2 , - 6
= - 2 , 6
The graph so plotted as shown . Answer
