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3 years ago

The difference between the roots of the quadratic equation x2 -14x +q =0 is 6. Find q

Mathematics

1 answer:

Irina-Kira [14]3 years ago

3 0

9514 1404 393

Answer:

q = 40

Step-by-step explanation:

When the quadratic has roots p and r, it can be factored as ...

(x -p)(x -r) = x² -(p+r)x +pr

So, the sum of the roots is 14, and their difference is 6. This lets us find the roots from ...

p + r = 14

p - r = 6

2p = 20 . . . add the two equations

p = 10

r = 14 -p = 4

The value of interest is then ...

q = pr = (10)(4)

q = 40

The graph shows the roots to be 4 and 10, as we found.

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Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

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$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$

8 0

2 years ago

5/6 N=10 solve this problem. I could not put the six under the five where it belongs. please show the work

Andreyy89

5/6N = 10

Mutiply by 6/5

So N=12

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3 years ago

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olga_2 [115]

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3 years ago

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faust18 [17]

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torisob [31]

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