Y = 6, z = 2
~Hope this helped!~
(The first page is the beginning of the equation, and the next page is the ending)
~Hope this helped!~
(The first page is the beginning of the equation, and the next page is the ending)
The difference between the roots of the quadratic equation x2 -14x +q =0 is 6. Find q
1 answer:
9514 1404 393
Answer:
q = 40
Step-by-step explanation:
When the quadratic has roots p and r, it can be factored as ...
(x -p)(x -r) = x² -(p+r)x +pr
So, the sum of the roots is 14, and their difference is 6. This lets us find the roots from ...
p + r = 14
p - r = 6
2p = 20 . . . add the two equations
p = 10
r = 14 -p = 4
The value of interest is then ...
q = pr = (10)(4)
q = 40
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The graph shows the roots to be 4 and 10, as we found.
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