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prisoha [69]
3 years ago
15

I need help on this :,)

Mathematics
2 answers:
Stella [2.4K]3 years ago
5 0
4.5 times 2.5= 11.25
WARRIOR [948]3 years ago
5 0
The answer is 4.5x2.5=11.25
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A 2000 gallon fish aquarium can be filled by water flowing at a constant rate in 10 hours. When a decorativve rock is placed in
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Answer:

The volume of the rock is 13.368 cubic feet.

Step-by-step explanation:

The volume of the rock (V_{r}), measured in gallons, is equal to the volume of the fish aquarium without the decorative rock (V') minus the volume of the fish aquarium with the decorative rock (V''), both measured in gallons.

Since the water flow is at constant rate, the volume of the rock is expressed by the following equation:

V_{r} = V' - V''

V_{r} = \dot V \cdot (\Delta t_{1}-\Delta t_{2}) (1)

Where:

\dot V - Flow rate, measured in gallons per hour.

\Delta t_{1} - Filling time of the fish aquarium without the decorative rock, measured in hours.

\Delta t_{2} - Filling time of the fish aquarium with the decorative rock, measured in hours.

And the flow rate is:

\dot V = \frac{2000\,gal}{10\,h}

\dot V = 200\,\frac{gal}{h}

The flow rate is 200 gallons per hour.

If we know that \dot V = 200\,\frac{gal}{h}, \Delta t_{1} = 10\,h and \Delta t_{2} = 9.5\,h, then the volume of the rock is:

V_{r} = \left(200\,\frac{gal}{h}\right)\cdot (10\,h-9.5\,h)

V_{r} = 100\,gal

V_{r} = 13.368\,ft^{3}

The volume of the rock is 13.368 cubic feet.

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