Answer:
The upper limit of the 95% confidence interval is:
C.I_u = 200 + (58.8/
)
Step-by-step explanation:
The formula is given as:
C.I = μ ± Z*σ/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
The upper limit => C.I_u = μ + Z*σ/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
The lower limit => C.I_l = μ - Z*σ/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
The sample size (n) is not stated in the question. Hence, we calculate the upper limit with respect to n.
The upper limit => C.I_u = 200 + 1.96*(30/
)
= 200 + (1.96*30)/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
= 200 + 58.8/![\sqrt{n}](https://tex.z-dn.net/?f=%5Csqrt%7Bn%7D)
I can't see images.
Can you tell me what is looks like?
6/12 or 1/2 I hope this was the right answer and helped you
Answer:
1/2
Step-by-step explanation:
(-2-(-1))/(-4-(-2))=1/2
The answer is eighty/ eighty-two