Question 3 find the x -intercept(s) and the coordinates of the vertex for the parabola

Mathematics

1 answer:

Olegator [25]3 years ago

3 0

is there a picture? if there is I cant see it

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If sin theta = 2/3, which of the following are possible

Ira Lisetskai [31]

Sin ø = opposite/hypotenuse = 2/3, cos ø = adjacent/hypotenuse = ?/3, tan ø = opposite/adjacent = 2/?, sec ø = 1/cos ø

to solve ?, Pythagorean theorem must be applied
hypotenuse^2 = adjacent^2 + opposite^2

Manipulating the equation to find the adjacent value = ?

adjacent = sqrt(hypotenuse^2 - opposite^2) = sqrt(9-4)
adjacent = sqrt(5)

so cos ø = sqrt(5)/3, tan ø = 2/sqrt(5) and sec <span>ø = 3/sqrt(5) since the value is positive the possible equivalent trigonometric function should be positive, the answer should be b </span>

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3 years ago

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Are the areas squared? So then are the answers in the thousands??

vfiekz [6]

Answer:

Yes, area units are squared (and volume units are cubed). The answers are:

a. 7.5 in
b. 12 in
c. 16.5 in

Step-by-step explanation:

Finding the area of a square or rectangle just involves multiplying the measures of both sides. So to find the measures of the missing sides, you need to divide the given area by the given side.

(Area)/(Known side)=(Unknown Side)

The units get squared because they're being multiplied... I'm not really sure how else to put it so sorry if it's still weird. It's like (x)(x)=x² but with the units; which are inches in this case.

The units pretty much always follow mathematical rules if your keeping track of them. Multiplying like units results in squared (for areas) or cubed (for volumes) units and dividing units gives you a ratio (like miles/hour). Adding and subtracting them won't change their degrees, but you also can't mix unlike unit degrees (in+in² can't be performed). Units will reduce if you divide or multiply them in certain ways too(miles/hour multiplied by hours will give you just the miles); but I digress.

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4 years ago

A circle with a circumference of 51 inches to find the area

Kaylis [27]

$\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=51 \end{cases}\implies 51=2\pi r\implies \boxed{\cfrac{51}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \implies A=\pi \left( \cfrac{51}{2\pi } \right)^2\implies A=\cfrac{51^2}{2^2\pi }\implies A\approx 206.98$