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Andrews [41]
2 years ago
10

15/3 + (6,5 + 4,2) - 0,6 Please show your work, thank you :)

Mathematics
1 answer:
kifflom [539]2 years ago
3 0

Answer:

15/3 + (6.5 + 4.2) - 0.6 = 15.1

Step-by-step explanation:

You can first reduce the fraction to 5 when you multiply by 3, then calculate what's in the parenthesis. So now you have 5 + 10.7 - 0.6, then just solve from left to right. Hope this helps

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The transformation of g(x)=15tanx would be achieved by shifting y=tanx graph 15 right. This transformation will cause x'=x+15. This will change the value from tan x into tan(x+15)
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Steven's family needs a new microwave. There is one on sale that measures 20 inches by 14 inches by 11 inches. What is the volum
Dahasolnce [82]

Answer:

3,080 in³

Step-by-step explanation:

To find the volume you use the formula

Length*Width*Height= Volume

So,

14*11*20 = 3080

and you unit will be cubed because volume is cubed!

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3 years ago
41 kilometers to meter
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Step-by-step explanation:

multiply the length value by 1000

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there are 2.54 centimeters in 1 inch. there are 100 centimeters in 1 meter.questionto the nearest meter, how many meters are in
Gre4nikov [31]

There are 7 meters in 279 inches.

  • There are 2.54 centimeters in 1 inch.
  • There are 100 centimeters in 1 meter.
  • The number of inches is given to be 279.
  • Unit conversion is a multi-step procedure that includes multiplying or dividing by a numerical factor, determining the appropriate number of significant digits, and rounding.
  • First of all, we need to convert inches to centimeters.
  • 1 inch equals 2.54 centimeters.
  • 279 inches equals 2.54*279 centimeters.
  • 279 inches equals 708.66 centimeters.
  • Now, we need to convert these centimeters into meters.
  • Meters in 100 centimeters = 1
  • Meters in 1 centimeters = 1/100
  • Meters in 708.66 centimeters = (1/100)*708.66
  • Meters in 708.66 centimeters = 7.0866
  • Thus, there are approximately 7 meters in 279 inches.

To learn more about unit conversion, visit :

brainly.com/question/11543684

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8 0
1 year ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
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