He can make 3 batches of soup.
Starting with 10 pounds of tomatoes and taking out the number of pounds he sets aside for spaghetti sauce, 2.8, we have:
10-2.8 = 7.2 pounds left.
0.2 is read as "two tenths," so 7.2 = 7 2/10
We divide this remaining number of pounds by 2 2/5 for each batch of soup:
7 2/10 ÷ 2 2/5
Convert each to an improper fraction:
72/10 ÷ 12/5
Multiply by the reciprocal:
72/10 × 5/12 = 360/120 = 3
i wish that i could help you but I just dont understand it... I am sorry
Answer:
8% or 0.08
Step-by-step explanation:
Probability of missing the first pass = 40% = 0.40
Probability of missing the second pass = 20% = 0.20
We have to find the probability that he misses both the passes. Since the two passes are independent of each other, the probability that he misses two passes will be:
Probability of missing 1st pass x Probability of missing 2nd pass
i.e.
Probability of missing two passes in a row = 0.40 x 0.20 = 0.08 = 8%
Thus, there is 8% probability that he misses two passes in a row.
Answer:
No mabey c
Step-by-step explanation:
Answer:
B-is correct
Step-by-step explanation:
y=a(x-h)^2+k
-k -k
y-k=a(x-h)^2
:(x-h)^2 :(x-h)^2
(y-k)/(x-h)^2 =a
