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Dvinal [7]
3 years ago
15

Write a polynomial function in standard form with given zero x=2,-1,-5

Mathematics
1 answer:
LekaFEV [45]3 years ago
4 0

Answer:

Done below!

Step-by-step explanation:

(x - root)

(x - 2)(x - (-1))(x - (-5)) = (x - 2)(x + 1)(x + 5)

(x^{2} +x-2x-2)(x+5)=(x^{2} -x-2)(x+5)=x^{3}+5x^{2}-x^{2}   -5x-2x-10\\\\=x^{3}+4x^{2} -7x-10

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Step-by-step explanation:

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The length of a picture frame is 6 inches more than the width. For what values of x is the perimeter of the picture frame greate
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A geometric sequence is defined by the general term tn = 75(5n), where n ∈N and n ≥ 1. What is the recursive formula of the sequ
andreyandreev [35.5K]
The correct answer is C) t₁ = 375, t_n=5t_{n-1}.

From the general form,
t_n=75(5)^n, we must work backward to find t₁.

The general form is derived from the explicit form, which is
t_n=t_1(r)^{n-1}.  We can see that r = 5; 5 has the exponent, so that is what is multiplied by every time. This gives us

t_n=t_1(5)^{n-1}

Using the products of exponents, we can "split up" the exponent:
t_n=t_1(5)^n(5)^{-1}

We know that 5⁻¹ = 1/5, so this gives us
t_n=t_1(\frac{1}{5})(5)^n
\\
\\=\frac{t_1}{5}(5)^n

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\frac{t_1}{5}=75

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t_1=375; t_n=t_{n-1}(5)

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