I would think you would use 1/3 of a cup but I am not sure.Hope it helps!
Answer:
P is exactly 3km east from the oil refinery.
Step-by-step explanation:
Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

So the cost of laying pipe under water with this distance is

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

We can find the minimum value of this by taking the 1st derivative and set it to 0

We can move the first term over to the right hand side and divide both sides by 400000


From here we can square up both sides






d = 3
So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.
The histogram is attached. Every column shows on the bottom the range of age and on the left the number of cars of that particular age.
In order to find the percentage of cars with less than 20 years or more than 40 years, you have to sum up the numbers of cars in the first two columns from left (age 0-9 and 10-19) and the last two (age 40-49 and 50-59).
The number of cars of requested age is: 3 + 2 + 0 + 3 = 8
Now, you need to calculate the total number of cars (sum the cars of every column): 3 + 2 + 8 + 4 + 0 + 3 = 20
Lastly, you need to calculate the ration between the cars of requested age and the total number of cars, and transform it into a percentage:
8 ÷ 20 = 0.40 = 40%
Therefore, your answer is
40%.
Answer: $9,900
Step-by-step explanation:
Convert the percentage into a decimal: 0.15
Multiply 0.15 by 18000
The product is 2700
Multiply 2700 by the 3 years
The product is 8100
Subtract 8100 from 18000
The result is $9,900
Answer:
Its either 4 or 4.6
Step-by-step explanation:
I used multiplication.