2x2=4
It is just like adding 2 twice
2 + 2 = 4
2 x 2 = 4
X^2 + 6x - 4y + 5 = 0
4y = x^2 + 6x + 5
y = 1/4x^2 + 3/2x + 5/4
Since, x is the squred part and x^2 has a positive coefficient, therefore, the graph opens up.
Answer:
145 x
Step-by-step explanation:
<span>f(x) = (x^2-16) / (x+3)
f(x) has no horizontal asymptote.
Vertical assymptote is x = -3
Dividing the numerator by the denominator gives x - 3 remainder -7. Therefore, the oblique assymptote is x - 3.
</span>
<span>the vertical asymptotes of the function f(x) = (5x + 1) / (x^2 + x - 6) = (5x + 1)/(x - 2)(x + 3) is x = 2 and x = -3.
</span><span>the zeros of the function f(x) = (3x^2 - 3x - 6 ) / (3x - 6)</span> = (3x^2 + 3x - 6x - 6) / (3x - 6) = (3x(x + 1) - 6(x + 1)) / (3x - 6) = (3x - 6)(x + 1)/(3x - 6) = x + 1 is x = -1
<span>the
function f(x) = (x^2 + x - 12) / (x - 3) = (x - 3)(x + 4) / (x - 3) is --> disc = 3, x-int = (-4, 0), y-int = 4? basic shape =
straight line</span>
