We need to determine the radius and diameter of the circle. If the area of the circle is 10 pi in^2, then, according to the formula for the area of a circle,
A = 10 pi in^2 = pi*r^2. Thus, 10 in^2 = r^2, and r = radius of circle = sqrt(10) in.
Thus, the diam. of the circle is 2sqrt(10) in. This diam. has the same length as does the hypotenuse of one of the triangles making up the square.
Thus, [ 2*sqrt(10) ]^2 = x^2 + x^2, where x represents the length of one side of the square. So, 4(10) in^2 = 2x^2. Then:
40 in^2 = 2x^2, or 20 in^2 = x^2, and so the length x of one side of the square is sqrt(20). The area of the square is the square of this result:
Area of the square = x^2 = [ sqrt(20) ]^2 = 20 in^2 (answer). Compare that to the 10 pi sq in area of the circle (31.42 in^2).
Answer:
On the Y axis
Step-by-step explanation:
Week 15 they'll both weigh 181 lbs
Example: 3^4 would be 3x3x3x3
Answer:
Step-by-step explanation:
a=4 b=12
2a+3b=
2*4+3*12=
8+36=
44
a²-b+10=
4²-12+10=
4*4-2=
16-2=
14
(ab)²-(a+b)²=
(4*12)²-(4+12)²=
48²-16²=
(48+16)(48-16)=
64*32=
2048