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Alona [7]
3 years ago
5

HURRY I NEED HELP NOW PLS. For his lunch, David is making a sandwich that must consist of bread, cheese, and meat. David can cho

ose from white, French or rye bread, either American or Swiss cheese, and the choice of turkey, ham or pastrami as a meat. Create a tree diagram to represent the combinations of bread, cheese, and meat David could make for his sandwich
Mathematics
1 answer:
Tom [10]3 years ago
8 0

3 types of bread, 2 types of cheese, and 3 types of meat.

I have attempted a tree diagram below:

A—> american cheese

S—>Swiss cheese

T—>turkey

P—>pastrami

H—>ham

white bread french bread rye bread

| | |——————- —————- -—————

| | | | | | | | |

T H. P. T. H. P. T. H. P

| | | | | |. | | |

—- —- —- —- —- —- —- —- —-

| | | | | | | | | | | | | | | | | |

A S A. S. A. S A. S. A. S A. S. A. S. A. S A S

Therefore you can know the number of combinations by counting the branches at the bottom so there are 18 combinations total. I hope this helps

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<h3>3 Answers:</h3>
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===================================

Explanation:

If we plug the coordinates of point A into the inequality, then we get

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That last inequality is a true statement since 9 is to the right of -2 on the number line. That means (10,-1) is a solution. Choice A is one of the answers

Choices B and D are also answers for similar reasons.

Something like choice C is not a solution because

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You should find that choice E is false as well.

---------------------

If you graphed the inequality and all of the points mentioned (see below), then you can visually confirm the answers. Notice how points A, B and D are in the blue shaded region which is the solution set.

The point E on the boundary does not count as a solution. This is due to the lack of "or equal to" portion of the inequality sign. That visually shows point E is not a solution. Point C isn't a solution either as it's nowhere near the blue shaded region.

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I don’t know what I’m solving for so I solved for h and with that it should be h=q/2+m/2

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