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Alona [7]
3 years ago
5

HURRY I NEED HELP NOW PLS. For his lunch, David is making a sandwich that must consist of bread, cheese, and meat. David can cho

ose from white, French or rye bread, either American or Swiss cheese, and the choice of turkey, ham or pastrami as a meat. Create a tree diagram to represent the combinations of bread, cheese, and meat David could make for his sandwich
Mathematics
1 answer:
Tom [10]3 years ago
8 0

3 types of bread, 2 types of cheese, and 3 types of meat.

I have attempted a tree diagram below:

A—> american cheese

S—>Swiss cheese

T—>turkey

P—>pastrami

H—>ham

white bread french bread rye bread

| | |——————- —————- -—————

| | | | | | | | |

T H. P. T. H. P. T. H. P

| | | | | |. | | |

—- —- —- —- —- —- —- —- —-

| | | | | | | | | | | | | | | | | |

A S A. S. A. S A. S. A. S A. S. A. S. A. S A S

Therefore you can know the number of combinations by counting the branches at the bottom so there are 18 combinations total. I hope this helps

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Answer:

We conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

Step-by-step explanation:

We are given that Bottles of a popular cola drink are supposed to contain 300 ml of cola. The distribution of the contents is normal with standard deviation of 3 ml.

A student who suspects that the bottler is under-filling measures the contents of six bottles. The results are: 299.4, 297.7, 301.0, 298.9, 300.2, 297.0

<u><em>Let </em></u>\mu<u><em> = mean contents of cola bottles.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq  300 ml   {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}

Alternate Hypothesis, H_A : \mu < 300 ml   {means that the mean contents of cola bottles is less than the advertised 300 ml}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about the population standard deviation;

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where, \bar X = sample mean contents of cola bottle = \frac{\sum X}{n} = 299.03 ml

            \sigma = population standard deviation = 3 ml

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So, <em><u>test statistics</u></em>  =  \frac{299.03-300}{\frac{3}{\sqrt{6} } }     

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<em>Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -0.792 > -1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

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