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Naily [24]
3 years ago
12

How can I write repeated multiplication using powers?

Mathematics
1 answer:
andrew-mc [135]3 years ago
8 0
Example: 3^4 would be 3x3x3x3
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What is a number n is at least 4
beks73 [17]
That inequality can be written as n >= 4

The ">=" represents greater than or equal to. On paper you would just add a horizontal line under the ">" and not include the "="
3 0
3 years ago
Which group contains triangles that are all similar?
torisob [31]

Answer:

Triangles represented by option B are similar triangles.

Step-by-step explanation:

Please find the attachment.

We have been given 4 group of triangles and we are asked to find which group contains similar triangles.

A. We can see from our diagram that triangles provided in option A are not similar.

The first triangle is an isosceles right triangle as it has 2 angles each having measure 45 degrees. By angle sum property the measure of 3rd angle will be:

180^o-(45^o+45^o)=180^o-90^o=90^o

The second triangle is an equilateral triangle as all the sides equal to 7 units, so all angles will be equal to 60 degrees.

The 3rd triangle is an isosceles triangle as  it has 2 angles each having measure 53 degrees. By angle sum property the measure of 3rd angle will be:

180^o-(53^o+53^o)=180^o-106^o=74^o

We can see that none of the triangles have same angle measures, therefore, option A is not a correct choice.

B. The triangles provided in option B are similar triangles as each triangle have one right angle and they are sharing the same vertex.

Let us assume that the common vertex has x degrees angle, then by angle sum property the measure of 3rd angle in each triangle will be 180-90-x=90-x degrees. Therefore, the triangles provided in option B are similar triangles by AAA similarity theorem.

C. The triangles provided in option C are not similar triangles as we are not told that the given lines are parallel or not. In addition the bottom figure is a quadrilateral as it has 4 angles, Therefore, the given triangles are not similar triangles.

D. We can see that our given triangles have vertical angles, so their measure will be 32 degrees. Since the given side lengths are different, therefore, this group of triangles is not similar.

5 0
3 years ago
Read 2 more answers
A number that multiplies a variable in a term is a ___
adelina 88 [10]
It’s gonna be B coefficient
4 0
3 years ago
Please help mee <br><br> help help
Damm [24]

Answer:

So, to 1 d.p. 7 is about 23% out of 30. (7 of 30=23%)

Step-by-step explanation:

7/30 x 100 =23.3333333333% or 70/3%.

6 0
2 years ago
An article written for a magazine claims that 78% of the magazine's subscribers report eating healthily the previous day. Suppos
Schach [20]

Answer:

89.44% probability that less than 80% of the sample would report eating healthily the previous day

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.78, n = 675

So

\mu = E(X) = np = 675*0.78 = 526.5

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{675*0.78*0.22} = 10.76

What is the approximate probability that less than 80% of the sample would report eating healthily the previous day?

This is the pvalue of Z when X = 0.8*675 = 540. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{540 - 526.5}{10.76}

Z = 1.25

Z = 1.25 has a pvalue of 0.8944

89.44% probability that less than 80% of the sample would report eating healthily the previous day

8 0
3 years ago
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