1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elanso [62]
2 years ago
15

Assume that 75 was the mean test score on an exam, with a standard deviation of 4 points.

Mathematics
1 answer:
Tems11 [23]2 years ago
5 0

Answer:

68%

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean of 75, standard deviation of 4.

What percent had scores between 67 and 75?

67 = 71 - 4

75 = 71 + 4

Within 1 standard deviation of the mean, so, by the Empirical Rule, 68%.

You might be interested in
Which of the following is not a property of mathematical proofs?
Contact [7]

There are no properties of mathematical proofs
on the list of choices that you have offered.

7 0
3 years ago
Which pair of angles are corresponding angles
Arte-miy333 [17]
Answer is C
<3 and <7
-----------
3 0
3 years ago
Read 2 more answers
We have 4different boxesand 6different objects. We want to distribute the objects into the boxes such that at no box is empty. I
Musya8 [376]

Answer:

Following are the solution to this question:

Step-by-step explanation:

They provide various boxes or various objects.  It also wants objects to be distributed into containers, so no container is empty.  All we select k objects of r to keep no boxes empty, which (r C k) could be done.  All such k artifacts can be placed in k containers, each of them in k! Forms. There will be remaining (r-k) objects. All can be put in any of k boxes.  Therefore, these (r-k) objects could in the k^{(r-k)} manner are organized.  Consequently, both possible ways to do this are

=\binom{r}{k} \times k! \times k^{r-k}\\\\=\frac{r! \times k^{r-k}}{(r-k)!}

Consequently, the number of ways that r objects in k different boxes can be arranged to make no book empty is every possible one

= \frac{r!k^{r-k}}{(r-k)!}

5 0
3 years ago
Simplify the expression​
ycow [4]

Answer:

4k(2k² - 5k - 4) + 5(2k² - 5k - 4)

8k³ - 20k² - 16k + 10k² -25k - 20

8k³ - 10k² - 41k - 20

Thus its G

7 0
3 years ago
Read 2 more answers
Max’s pet worm lives in a cardboard box that has a volume of 80 cubic centimeters.
Temka [501]
C

length= 10 cm
width= 4 cm
height= 2 cm

10*4= 40
40*2= 80

8 0
3 years ago
Other questions:
  • Double Points! Write an inequality that models a real-world situation. Describe your situation and what the variable x represent
    11·2 answers
  • Can someone help me please :(
    11·1 answer
  • I need some help with this question :/
    7·2 answers
  • Gisela is putting her 35 CD into categories. She has 11 that are pop music, and she has 3 times as many rock CDs as she has clas
    11·1 answer
  • How do you collect and distribute this?
    9·1 answer
  • A circular foundation has a radius of 9.4 feet. Find it's diameter and circumference to the nearest tenth
    11·2 answers
  • A farmer collected 12 dozen eggs from her chickens. She sold 5/6 of the eggs to the farmers market and gave the rest to friends
    7·2 answers
  • Please help, will give brainliest!
    9·1 answer
  • Ayo runs a fairground game.In each turn, a player rolls a fair dice numbered 1 - 6 and spins a fair spinner numbered 1 - 12.It c
    11·1 answer
  • Write an equation of the line that passes through (18,2) and is parallel to the line 3y - x= - 12 .
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!