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exis [7]
2 years ago
9

a vendor is thinking about changing the number of sweatshirts he brings to tan event. to make sure he doesn't run out, he plans

to bring more of the size most likely to be sold. the table shows the number of sweatshirts of each size sold at the vendors last event and the number he had for sale. which size should he bring more of?

Mathematics
1 answer:
NISA [10]2 years ago
4 0

The sweatshirt size which the vendor should bring more of by virtue of that which is most likely to be sold is; Choice A; Extra-large.

<h3>Which sweatshirt size should the vendor bring more of?</h3>

If follows from the task content that the

ratio of extralarge shirts sold relative to the quantity he had to sell is

= 99/108

= 11/12,

This is a ratio which is larger than any other shirt.

Consequently, the vendor must bring more of the X-large shirts to avoid running out of them.

Read more on ratios;

brainly.com/question/13513438

#SPJ1

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Answer:

The probability of getting a red jelly bean both of the times is 0.028.

Step-by-step explanation:

First we have that in the box are 12 jelly beans having 2 red and 10 blue. The probability of getting one of the red jelly beans are the sum of the probability of the 2 red jelly beans, that is:

ProbabilityRed=\frac{1}{12} +\frac{1}{12}=\frac{2}{12}

Now we can calculate the probability of getting the red jelly bean twice, this will be the product of the probability of getting each one, is the same probability for the second chance because we are getting the jelly bean back in the box, this is:

ProbabilityBothRed=\frac{2}{12} *\frac{2}{12}=\frac{4}{144}  =\frac{1}{36} =0.028

Now we have that the probability of getting a red jelly bean both of the times is 0.028.

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3 years ago
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Answer:

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When you plug those values into the x equation you get x=\frac{1}{6}.

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MAVERICK [17]

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4 0
3 years ago
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