Answer: 21/44
Step-by-step explanation:
Given that:
Bag contains :
6 red apples
6 yellow apples
Number of samples drawn = 3
Probability that sample contains more red than yellow :
Then from the three samples, red = 2 and yellow = 1 or red for all 3
Prob of RRR = (6/12)(5/11)(4/10)= 120 / 1320
Prob RRY = (6/12)(5/11)(6/10)= 150/1320
Prob RYR is (6/12)(6/11)(5/10)= 180/1320
Prob YRR is (6/12)(6/11)(5/10)=180/1320
120/1320 + 150/1320 + 180/1320 +. 180/1320 = 630/1320 =126/264 = 42/88 = 21/44
Normally when dealing with coins the probability of getting heads or tails is 0.5 each. However in this case since its an unfair coin, the probability of getting heads is 0.2.
H - head
T - tails
R - red marble
pr (H) = 0.2
urn
6 red and 4 blue
pr (T) = 0.8
urn
3 red and 5 blue
when heads is obtained
red - 6/10 -0.6
blue - 4/10 - 0.4
therefore when multiplying with 0.2 probability of getting heads
pr (R ∩ H) red - 0.6*0.2 = 0.12
when tails is obtained
red - 3/8 - 0.375
blue - 5/8 - 0.625
when multiplying with 0.8 probability of getting tails
pr (R ∩ T) red - 0.375 * 0.8 = 0.3
using bayes rule the answer can be found out,
the following equation is used;
pr (H | R) = pr (R ∩ H) / {pr (R ∩ H) + pr (R ∩ T)}
= 0.12 / (0.12 + 0.3)
= 0.12 / 0.42
= 0.286
the final answer is 0.286
Answer:
c
Step-by-step explanation:
the problem is saying the same thing twice just om different words
If u take you answer as x and do the problem u will see that they are equal so u would have to have a different answers for x or say -6.1 is greater than or equal to -17.4 + 11.3
