Question

Can someone help me with the first one pls

Answer 1

Answer:

The answer of the first one is b

Step-by-step explanation:

going left is negative and going up is positive

Answer 2

Answer:

12. a

13a. (-3, 2)

13b.$12\sqrt{2}$

13c. $( x +3 )^2 + ( y - 2 )^2 = 288$

Step-by-step explanation:

13a. Graph endpoints and find the center, and to find the center we can use the midpoint formula.

$midpoint = (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\ = (\frac{-9+3}{2},\frac{-4+8}{2})\\= (\frac{-6}{2},\frac{4}{2})\\ = (-3,2)$

13b. Use given points and use distance formula to find radius.

$distance = \sqrt{({x_2-x_1})^2+({y_2-y_1})^2}\\= \sqrt{({3-(-9)})^2+({8-(-4)})^2}\\= \sqrt{({3+9})^2+({8+4})^2}\\=\sqrt{({12})^2+({12})^2}\\ =\sqrt{({12})^2+({12})^2}\\= \sqrt{144+144} = \sqrt{288} = 12\sqrt{2}$

13c. Refer back to 13a and 13b to setup the equation of the circle.

$( x - h )^2 + ( y - k )^2 = r^2\\( x - (-3) )^2 + ( y - 2 )^2 = (12\sqrt{2})^2\\( x +3 )^2 + ( y - 2 )^2 = 288$

Sorry if it looks long but I hope that helps!